Réitigh ∫ z/(z-1)^2(z+2)

$$\int \frac { z } { ( z - 1 ) ^ { 2 } ( z + 2 ) }$$

Luacháil

$$\frac{xz}{\left(z+2\right)\left(z-1\right)^{2}}+С$$

Céimeanna Réitigh

Aimsigh suimeálaithe do \frac{z}{\left(z-1\right)^{2}\left(z+2\right)} ag baint úsáid as an tábla do suimeálaithe coitianta riail\int a\mathrm{d}x=ax.

$$\frac{z}{\left(z-1\right)^{2}\left(z+2\right)}x$$

Simpligh.

$$\frac{zx}{\left(z-1\right)^{2}\left(z+2\right)}$$

Má tá F\left(x\right) mar frithdhíorthach do f\left(x\right), beidh tacar do frithdhíorthach uile do f\left(x\right) a thabhairt ag F\left(x\right)+C. Mar sin de, cur an comhtháthú leanúnach C\in \mathrm{R} don toradh.

$$\frac{zx}{\left(z-1\right)^{2}\left(z+2\right)}+С$$

Difreálaigh w.r.t. x

$$\frac{z}{\left(z+2\right)\left(z-1\right)^{2}}$$