Réitigh x-4/x+2geq2

$$\frac{ x-4 }{ x+2 } \geq 2$$

Réitigh do x.

$$x\in [-8,-2)$$

Céimeanna Réitigh

Denominator x+2 cannot be zero since division by zero is not defined. There are two cases.

$$x+2>0 x+2<0$$

Consider the case when x+2 is positive. Move 2 to the right hand side.

$$x>-2$$

The initial inequality does not change the direction when multiplied by x+2 for x+2>0.

$$x-4\geq 2\left(x+2\right)$$

Multiply out the right hand side.

$$x-4\geq 2x+4$$

Move the terms containing x to the left hand side and all other terms to the right hand side.

$$x-2x\geq 4+4$$

Cuir téarmaí cosúla le chéile.

$$-x\geq 8$$

Roinn an dá thaobh faoi -1. Tá -1 <0, mar sin athraítear treo na héagothromóide.

$$x\leq -8$$

Consider condition x>-2 specified above.

$$x\in \emptyset$$

Now consider the case when x+2 is negative. Move 2 to the right hand side.

$$x<-2$$

The initial inequality changes the direction when multiplied by x+2 for x+2<0.

$$x-4\leq 2\left(x+2\right)$$

Multiply out the right hand side.

$$x-4\leq 2x+4$$

Move the terms containing x to the left hand side and all other terms to the right hand side.

$$x-2x\leq 4+4$$

Cuir téarmaí cosúla le chéile.

$$-x\leq 8$$

Roinn an dá thaobh faoi -1. Tá -1 <0, mar sin athraítear treo na héagothromóide.

$$x\geq -8$$

Consider condition x<-2 specified above.

$$x\in [-8,-2)$$

Is é an réiteach deireanach ná suim na réiteach a fuarthas.

$$x\in [-8,-2)$$