Réitigh 20/sqrt{6-sqrt{2}}

$$\frac{ 20 }{ \sqrt{ 6 } - \sqrt{ 2 } }$$

Luacháil

$$5\left(\sqrt{2}+\sqrt{6}\right)\approx 19.318516526$$

Céimeanna Réitigh

Iolraigh an t-uimhreoir agus an t-ainmneoir faoi \sqrt{6}+\sqrt{2} chun ainmneoir \frac{20}{\sqrt{6}-\sqrt{2}} a thiontú in uimhir chóimheasta.

$$\frac{20\left(\sqrt{6}+\sqrt{2}\right)}{\left(\sqrt{6}-\sqrt{2}\right)\left(\sqrt{6}+\sqrt{2}\right)}$$

Mar shampla \left(\sqrt{6}-\sqrt{2}\right)\left(\sqrt{6}+\sqrt{2}\right). Is féidir iolrúchán a athrú ó bhonn go dtí difríocht na gcearnóg ag úsáid na rialach seo: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$\frac{20\left(\sqrt{6}+\sqrt{2}\right)}{\left(\sqrt{6}\right)^{2}-\left(\sqrt{2}\right)^{2}}$$

Cearnóg \sqrt{6}. Cearnóg \sqrt{2}.

$$\frac{20\left(\sqrt{6}+\sqrt{2}\right)}{6-2}$$

Dealaigh 2 ó 6 chun 4 a fháil.

$$\frac{20\left(\sqrt{6}+\sqrt{2}\right)}{4}$$

Roinn 20\left(\sqrt{6}+\sqrt{2}\right) faoi 4 chun 5\left(\sqrt{6}+\sqrt{2}\right) a fháil.

$$5\left(\sqrt{6}+\sqrt{2}\right)$$

Úsáid an t-airí dáileach chun 5 a mhéadú faoi \sqrt{6}+\sqrt{2}.

$$5\sqrt{6}+5\sqrt{2}$$