Réitigh x^4/4-x^3+x^2+1+c=0

$$\frac{ { x }^{ 4 } }{ 4 } - { x }^{ 3 } + { x }^{ 2 } +1+c=0$$

Réitigh do c.

$$c=-\frac{\left(x^{2}+2\right)^{2}}{4}+x^{3}$$

Céimeanna chun Cothromóidí Líneacha a Réiteach

Méadaigh an dá thaobh den chothromóid faoi 4.

$$x^{4}-4x^{3}+4x^{2}+4+4c=0$$

Bain x^{4} ón dá thaobh. Is ionann rud ar bith a dhealaítear ó nialas agus a shéanadh.

$$-4x^{3}+4x^{2}+4+4c=-x^{4}$$

Cuir 4x^{3} leis an dá thaobh.

$$4x^{2}+4+4c=-x^{4}+4x^{3}$$

Bain 4x^{2} ón dá thaobh.

$$4+4c=-x^{4}+4x^{3}-4x^{2}$$

Bain 4 ón dá thaobh.

$$4c=-x^{4}+4x^{3}-4x^{2}-4$$

Roinn an dá thaobh faoi 4.

$$\frac{4c}{4}=\frac{-\left(x^{2}+2\right)^{2}+4x^{3}}{4}$$

Má roinntear é faoi 4 cuirtear an iolrúchán faoi 4 ar ceal.

$$c=\frac{-\left(x^{2}+2\right)^{2}+4x^{3}}{4}$$

Roinn 4x^{3}-\left(x^{2}+2\right)^{2} faoi 4.

$$c=-\frac{\left(x^{2}+2\right)^{2}}{4}+x^{3}$$