Réitigh x^2/y^2=3,x^2*y^2=7 | Réiteoir Mata Microsoft

Réitigh do x,y. (complex solution)

x=\sqrt[4]{21}\approx 2.140695143\text{, }y=\frac{\sqrt[4]{189}}{3}\approx 1.235930917

x=\sqrt[4]{21}\approx 2.140695143\text{, }y=-\frac{\sqrt[4]{189}}{3}\approx -1.235930917

x=-\sqrt[4]{21}\approx -2.140695143\text{, }y=\frac{\sqrt[4]{189}}{3}\approx 1.235930917

x=-\sqrt[4]{21}\approx -2.140695143\text{, }y=-\frac{\sqrt[4]{189}}{3}\approx -1.235930917

x=\sqrt[4]{21}i\approx 2.140695143i\text{, }y=\frac{\sqrt[4]{189}i}{3}\approx 1.235930917i

x=\sqrt[4]{21}i\approx 2.140695143i\text{, }y=-\frac{\sqrt[4]{189}i}{3}\approx -0-1.235930917i

x=-\sqrt[4]{21}i\approx -0-2.140695143i\text{, }y=\frac{\sqrt[4]{189}i}{3}\approx 1.235930917i

x=-\sqrt[4]{21}i\approx -0-2.140695143i\text{, }y=-\frac{\sqrt[4]{189}i}{3}\approx -0-1.235930917i

Réitigh do x,y.

x=-\sqrt[4]{21}\approx -2.140695143\text{, }y=-\frac{\sqrt[4]{189}}{3}\approx -1.235930917

x=-\sqrt[4]{21}\approx -2.140695143\text{, }y=\frac{\sqrt[4]{189}}{3}\approx 1.235930917

x=\sqrt[4]{21}\approx 2.140695143\text{, }y=-\frac{\sqrt[4]{189}}{3}\approx -1.235930917

x=\sqrt[4]{21}\approx 2.140695143\text{, }y=\frac{\sqrt[4]{189}}{3}\approx 1.235930917

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Tráth na gCeist

Algebra

5 fadhbanna cosúil le:

\frac { x ^ { 2 } } { y ^ { 2 } } = 3 , x ^ { 2 } \times y ^ { 2 } = 7

Fadhbanna den chineál céanna ó Chuardach Gréasáin

Can someone help me simplify this please? \displaystyle\frac{{{x}^{{2}}-{y}^{{2}}}}{{y}^{{2}}}\times\frac{{y}^{{3}}}{{{y}-{x}}}

https://socratic.org/questions/can-someone-help-me-simplify-this-please-2

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https://socratic.org/questions/how-do-you-simplify-2x-1-3y-2-2-times-3x-2-5y

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https://socratic.org/questions/how-do-you-simplify-frac-2x-2-y-x-3-3-times-frac-y-1-2x-2

\displaystyle{32}{x}^{{-{{1}}}}{y} Explanation: Given, \displaystyle{\left[\frac{{{2}{x}^{{2}}{y}}}{{x}^{{3}}}\right]}^{{3}}.{\left[\frac{{y}^{{1}}}{{{2}{x}}}\right]}^{{-{{2}}}} \displaystyle\Rightarrow{\left[\frac{{{2}{y}}}{{x}}\right]}^{{3}}.{\left[\frac{{{2}{x}}}{{y}}\right]}^{{2}} ...

How do you simplify \displaystyle\frac{{{3}{x}}}{{{6}{x}^{{2}}}}\times\frac{{{2}{y}-{6}}}{{{y}-{3}}} ?

https://socratic.org/questions/how-do-you-simplify-3x-6x-2-times-2y-6-y-3

Konstantinos Michailidis May 26, 2016 It is \displaystyle\frac{{{3}{x}}}{{{6}{x}^{{2}}}}\times\frac{{{2}{y}-{6}}}{{{y}-{3}}}=\frac{{{3}{x}}}{{{2}{x}\cdot{3}{x}}}\times{\left(\frac{{{2}\cdot{\left({y}-{3}\right)}}}{{{y}-{3}}}\right)}=\frac{{\cancel{{{3}{x}}}}}{{{2}{x}\cdot\cancel{{{3}{x}}}}}\times{\left(\frac{{{2}\cdot\cancel{{{y}-{3}}}}}{\cancel{{{y}-{3}}}}\right)}=\frac{{1}}{{{2}{x}}}\times{2}=\frac{{1}}{{\cancel{{2}}\cdot{x}}}\cdot\cancel{{2}}=\frac{{1}}{{x}}

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https://socratic.org/questions/how-do-you-simplify-8-21-x-2y-3-times-7-16xy-2

See a solution process below: Explanation: First, rewrite the expression as: \displaystyle{\left(-\frac{{8}}{{21}}\times-\frac{{7}}{{16}}\right)}{\left({x}^{{2}}\times{x}\right)}{\left({y}^{{3}}\times{y}^{{2}}\right)}\Rightarrow ...

How to integrate the following

https://math.stackexchange.com/questions/2306208/how-to-integrate-the-following

Step 1: integrate wrt y. I=\int_1^2\int_1^2\frac{x}{x^2+y^2}\,dy\,dx=\int_1^2\left[\arctan\left(\frac yx\right)\right]_1^2\,dx=\int_1^2\arctan\left(\frac2x\right)-\arctan\left(\frac1x \right)\,dx ...

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