Réitigh r+2/r(r+3)-r-1/r(r+2)

$$\frac { r + 2 } { r ( r + 3 ) } - \frac { r - 1 } { r ( r + 2 ) }$$

Luacháil

$$\frac{2r+7}{r\left(r+2\right)\left(r+3\right)}$$

Céimeanna gearra réitigh

Chun cothromóidí a shuimiú nó a dhealú, fairsingigh iad chun a n-ainmneoirí a mheaitseáil. Is é an t-iolrach is lú coitianta de r\left(r+3\right) agus r\left(r+2\right) ná r\left(r+2\right)\left(r+3\right). Méadaigh \frac{r+2}{r\left(r+3\right)} faoi \frac{r+2}{r+2}. Méadaigh \frac{r-1}{r\left(r+2\right)} faoi \frac{r+3}{r+3}.

$$\frac{\left(r+2\right)\left(r+2\right)}{r\left(r+2\right)\left(r+3\right)}-\frac{\left(r-1\right)\left(r+3\right)}{r\left(r+2\right)\left(r+3\right)}$$

Tá an t-ainmneoir céanna ag \frac{\left(r+2\right)\left(r+2\right)}{r\left(r+2\right)\left(r+3\right)} agus \frac{\left(r-1\right)\left(r+3\right)}{r\left(r+2\right)\left(r+3\right)} agus, mar sin, is féidir iad a dhealú trína n-uimhreoirí a dhealú.

$$\frac{\left(r+2\right)\left(r+2\right)-\left(r-1\right)\left(r+3\right)}{r\left(r+2\right)\left(r+3\right)}$$

Déan iolrúcháin in \left(r+2\right)\left(r+2\right)-\left(r-1\right)\left(r+3\right).

$$\frac{r^{2}+2r+2r+4-r^{2}-3r+r+3}{r\left(r+2\right)\left(r+3\right)}$$

Cumaisc téarmaí comhchosúla in: r^{2}+2r+2r+4-r^{2}-3r+r+3.

$$\frac{2r+7}{r\left(r+2\right)\left(r+3\right)}$$

Fairsingigh r\left(r+2\right)\left(r+3\right)

$$\frac{2r+7}{r^{3}+5r^{2}+6r}$$

Fairsingigh

$$\frac{2r+7}{r\left(r+2\right)\left(r+3\right)}$$

Céimeanna gearra réitigh

Chun cothromóidí a shuimiú nó a dhealú, fairsingigh iad chun a n-ainmneoirí a mheaitseáil. Is é an t-iolrach is lú coitianta de r\left(r+3\right) agus r\left(r+2\right) ná r\left(r+2\right)\left(r+3\right). Méadaigh \frac{r+2}{r\left(r+3\right)} faoi \frac{r+2}{r+2}. Méadaigh \frac{r-1}{r\left(r+2\right)} faoi \frac{r+3}{r+3}.

$$\frac{\left(r+2\right)\left(r+2\right)}{r\left(r+2\right)\left(r+3\right)}-\frac{\left(r-1\right)\left(r+3\right)}{r\left(r+2\right)\left(r+3\right)}$$

Tá an t-ainmneoir céanna ag \frac{\left(r+2\right)\left(r+2\right)}{r\left(r+2\right)\left(r+3\right)} agus \frac{\left(r-1\right)\left(r+3\right)}{r\left(r+2\right)\left(r+3\right)} agus, mar sin, is féidir iad a dhealú trína n-uimhreoirí a dhealú.

$$\frac{\left(r+2\right)\left(r+2\right)-\left(r-1\right)\left(r+3\right)}{r\left(r+2\right)\left(r+3\right)}$$

Déan iolrúcháin in \left(r+2\right)\left(r+2\right)-\left(r-1\right)\left(r+3\right).

$$\frac{r^{2}+2r+2r+4-r^{2}-3r+r+3}{r\left(r+2\right)\left(r+3\right)}$$

Cumaisc téarmaí comhchosúla in: r^{2}+2r+2r+4-r^{2}-3r+r+3.

$$\frac{2r+7}{r\left(r+2\right)\left(r+3\right)}$$

Fairsingigh r\left(r+2\right)\left(r+3\right)

$$\frac{2r+7}{r^{3}+5r^{2}+6r}$$