Réitigh p/3p-4-2/pp-6

$$\frac { p } { 3 p - 4 } - \frac { 2 } { p p - 6 }$$

Luacháil

$$\frac{p^{3}-12p+8}{\left(3p-4\right)\left(p^{2}-6\right)}$$

Céimeanna gearra réitigh

Méadaigh p agus p chun p^{2} a fháil.

$$\frac{p}{3p-4}-\frac{2}{p^{2}-6}$$

Chun cothromóidí a shuimiú nó a dhealú, fairsingigh iad chun a n-ainmneoirí a mheaitseáil. Is é an t-iolrach is lú coitianta de 3p-4 agus p^{2}-6 ná \left(3p-4\right)\left(p^{2}-6\right). Méadaigh \frac{p}{3p-4} faoi \frac{p^{2}-6}{p^{2}-6}. Méadaigh \frac{2}{p^{2}-6} faoi \frac{3p-4}{3p-4}.

$$\frac{p\left(p^{2}-6\right)}{\left(3p-4\right)\left(p^{2}-6\right)}-\frac{2\left(3p-4\right)}{\left(3p-4\right)\left(p^{2}-6\right)}$$

Tá an t-ainmneoir céanna ag \frac{p\left(p^{2}-6\right)}{\left(3p-4\right)\left(p^{2}-6\right)} agus \frac{2\left(3p-4\right)}{\left(3p-4\right)\left(p^{2}-6\right)} agus, mar sin, is féidir iad a dhealú trína n-uimhreoirí a dhealú.

$$\frac{p\left(p^{2}-6\right)-2\left(3p-4\right)}{\left(3p-4\right)\left(p^{2}-6\right)}$$

Déan iolrúcháin in p\left(p^{2}-6\right)-2\left(3p-4\right).

$$\frac{p^{3}-6p-6p+8}{\left(3p-4\right)\left(p^{2}-6\right)}$$

Cumaisc téarmaí comhchosúla in: p^{3}-6p-6p+8.

$$\frac{p^{3}-12p+8}{\left(3p-4\right)\left(p^{2}-6\right)}$$

Fairsingigh \left(3p-4\right)\left(p^{2}-6\right)

$$\frac{p^{3}-12p+8}{3p^{3}-4p^{2}-18p+24}$$

Difreálaigh w.r.t. p

$$\frac{4\left(-p^{4}+9p^{3}-12p^{2}+16p-36\right)}{\left(\left(3p-4\right)\left(p^{2}-6\right)\right)^{2}}$$