Réitigh a^2-a-12/2a^2+adiv16-a^2/2a^2+9a+4

Luacháil

Fairsingigh

Tráth na gCeist

Polynomial

5 fadhbanna cosúil le:

Fadhbanna den chineál céanna ó Chuardach Gréasáin

https://socratic.org/questions/how-do-you-divide-frac-5p-3-3p-3-3p-div-frac-5p-3-9p-3-21p-2-12p

https://socratic.org/questions/how-do-you-divide-and-simplify-frac-6m-2-m-2-9m-2-4-div-frac-6m-2-4m-2m-2-3m

https://socratic.org/questions/how-do-you-divide-a-3-a-2-a-12-div-a-2-9-a-2-7a-12

https://socratic.org/questions/simplify-this-expression-1-2-2-3-2-3-1-2-4-2-11-hint-1-a-n-m-1-a-n-m-a-j-xx-a-k-

https://socratic.org/questions/how-do-you-evaluate-frac-a-2-3a-4a-2-16-div-frac-a-2-16-a-2-6a-8

https://socratic.org/questions/how-do-you-divide-and-simplify-frac-6b-a-2-b-2-t-2k-2-div-frac-3-a-b-2-2kt-2-3

Roinn

Cóipeáladh go dtí an ghearrthaisce

\frac{\left(a^{2}-a-12\right)\left(2a^{2}+9a+4\right)}{\left(2a^{2}+a\right)\left(16-a^{2}\right)}

Roinn \frac{a^{2}-a-12}{2a^{2}+a} faoi \frac{16-a^{2}}{2a^{2}+9a+4} trí \frac{a^{2}-a-12}{2a^{2}+a} a mhéadú faoi dheilín \frac{16-a^{2}}{2a^{2}+9a+4}.

\frac{\left(a-4\right)\left(a+3\right)\left(a+4\right)\left(2a+1\right)}{a\left(a-4\right)\left(-a-4\right)\left(2a+1\right)}

Fachtóirigh na sloinn nach bhfuil fachtóirithe cheana.

\frac{-\left(a-4\right)\left(-a-4\right)\left(a+3\right)\left(2a+1\right)}{a\left(a-4\right)\left(-a-4\right)\left(2a+1\right)}

Bain an comhartha diúltach in: 4+a.

\frac{-\left(a+3\right)}{a}

Cealaigh \left(a-4\right)\left(-a-4\right)\left(2a+1\right) mar uimhreoir agus ainmneoir.

\frac{-a-3}{a}

Fairsingigh an slonn.