Réitigh 3x^2+4-5/x^2+5x+4-2x/x+1+4/x+4

$$\frac { 3 x ^ { 2 } + 4 - 5 } { x ^ { 2 } + 5 x + 4 } - \frac { 2 x } { x + 1 } + \frac { 4 } { x + 4 }$$

Luacháil

$$\frac{\left(x-3\right)\left(x-1\right)}{\left(x+1\right)\left(x+4\right)}$$

Céimeanna gearra réitigh

Dealaigh 5 ó 4 chun -1 a fháil.

$$\frac{3x^{2}-1}{x^{2}+5x+4}-\frac{2x}{x+1}+\frac{4}{x+4}$$

Fachtóirigh x^{2}+5x+4.

$$\frac{3x^{2}-1}{\left(x+1\right)\left(x+4\right)}-\frac{2x}{x+1}+\frac{4}{x+4}$$

Chun cothromóidí a shuimiú nó a dhealú, fairsingigh iad chun a n-ainmneoirí a mheaitseáil. Is é an t-iolrach is lú coitianta de \left(x+1\right)\left(x+4\right) agus x+1 ná \left(x+1\right)\left(x+4\right). Méadaigh \frac{2x}{x+1} faoi \frac{x+4}{x+4}.

$$\frac{3x^{2}-1}{\left(x+1\right)\left(x+4\right)}-\frac{2x\left(x+4\right)}{\left(x+1\right)\left(x+4\right)}+\frac{4}{x+4}$$

Tá an t-ainmneoir céanna ag \frac{3x^{2}-1}{\left(x+1\right)\left(x+4\right)} agus \frac{2x\left(x+4\right)}{\left(x+1\right)\left(x+4\right)} agus, mar sin, is féidir iad a dhealú trína n-uimhreoirí a dhealú.

$$\frac{3x^{2}-1-2x\left(x+4\right)}{\left(x+1\right)\left(x+4\right)}+\frac{4}{x+4}$$

Déan iolrúcháin in 3x^{2}-1-2x\left(x+4\right).

$$\frac{3x^{2}-1-2x^{2}-8x}{\left(x+1\right)\left(x+4\right)}+\frac{4}{x+4}$$

Cumaisc téarmaí comhchosúla in: 3x^{2}-1-2x^{2}-8x.

$$\frac{x^{2}-1-8x}{\left(x+1\right)\left(x+4\right)}+\frac{4}{x+4}$$

Chun cothromóidí a shuimiú nó a dhealú, fairsingigh iad chun a n-ainmneoirí a mheaitseáil. Is é an t-iolrach is lú coitianta de \left(x+1\right)\left(x+4\right) agus x+4 ná \left(x+1\right)\left(x+4\right). Méadaigh \frac{4}{x+4} faoi \frac{x+1}{x+1}.

$$\frac{x^{2}-1-8x}{\left(x+1\right)\left(x+4\right)}+\frac{4\left(x+1\right)}{\left(x+1\right)\left(x+4\right)}$$

Tá an t-ainmneoir céanna ag \frac{x^{2}-1-8x}{\left(x+1\right)\left(x+4\right)} agus \frac{4\left(x+1\right)}{\left(x+1\right)\left(x+4\right)} agus, mar sin, is féidir iad a shuimiú trína n-uimhreoirí a shuimiú.

$$\frac{x^{2}-1-8x+4\left(x+1\right)}{\left(x+1\right)\left(x+4\right)}$$

Déan iolrúcháin in x^{2}-1-8x+4\left(x+1\right).

$$\frac{x^{2}-1-8x+4x+4}{\left(x+1\right)\left(x+4\right)}$$

Cumaisc téarmaí comhchosúla in: x^{2}-1-8x+4x+4.

$$\frac{x^{2}+3-4x}{\left(x+1\right)\left(x+4\right)}$$

Fairsingigh \left(x+1\right)\left(x+4\right)

$$\frac{x^{2}+3-4x}{x^{2}+5x+4}$$

Fairsingigh

$$\frac{x^{2}-4x+3}{\left(x+1\right)\left(x+4\right)}$$

Céimeanna gearra réitigh

Dealaigh 5 ó 4 chun -1 a fháil.

$$\frac{3x^{2}-1}{x^{2}+5x+4}-\frac{2x}{x+1}+\frac{4}{x+4}$$

Fachtóirigh x^{2}+5x+4.

$$\frac{3x^{2}-1}{\left(x+1\right)\left(x+4\right)}-\frac{2x}{x+1}+\frac{4}{x+4}$$

Chun cothromóidí a shuimiú nó a dhealú, fairsingigh iad chun a n-ainmneoirí a mheaitseáil. Is é an t-iolrach is lú coitianta de \left(x+1\right)\left(x+4\right) agus x+1 ná \left(x+1\right)\left(x+4\right). Méadaigh \frac{2x}{x+1} faoi \frac{x+4}{x+4}.

$$\frac{3x^{2}-1}{\left(x+1\right)\left(x+4\right)}-\frac{2x\left(x+4\right)}{\left(x+1\right)\left(x+4\right)}+\frac{4}{x+4}$$

Tá an t-ainmneoir céanna ag \frac{3x^{2}-1}{\left(x+1\right)\left(x+4\right)} agus \frac{2x\left(x+4\right)}{\left(x+1\right)\left(x+4\right)} agus, mar sin, is féidir iad a dhealú trína n-uimhreoirí a dhealú.

$$\frac{3x^{2}-1-2x\left(x+4\right)}{\left(x+1\right)\left(x+4\right)}+\frac{4}{x+4}$$

Déan iolrúcháin in 3x^{2}-1-2x\left(x+4\right).

$$\frac{3x^{2}-1-2x^{2}-8x}{\left(x+1\right)\left(x+4\right)}+\frac{4}{x+4}$$

Cumaisc téarmaí comhchosúla in: 3x^{2}-1-2x^{2}-8x.

$$\frac{x^{2}-1-8x}{\left(x+1\right)\left(x+4\right)}+\frac{4}{x+4}$$

Chun cothromóidí a shuimiú nó a dhealú, fairsingigh iad chun a n-ainmneoirí a mheaitseáil. Is é an t-iolrach is lú coitianta de \left(x+1\right)\left(x+4\right) agus x+4 ná \left(x+1\right)\left(x+4\right). Méadaigh \frac{4}{x+4} faoi \frac{x+1}{x+1}.

$$\frac{x^{2}-1-8x}{\left(x+1\right)\left(x+4\right)}+\frac{4\left(x+1\right)}{\left(x+1\right)\left(x+4\right)}$$

Tá an t-ainmneoir céanna ag \frac{x^{2}-1-8x}{\left(x+1\right)\left(x+4\right)} agus \frac{4\left(x+1\right)}{\left(x+1\right)\left(x+4\right)} agus, mar sin, is féidir iad a shuimiú trína n-uimhreoirí a shuimiú.

$$\frac{x^{2}-1-8x+4\left(x+1\right)}{\left(x+1\right)\left(x+4\right)}$$

Déan iolrúcháin in x^{2}-1-8x+4\left(x+1\right).

$$\frac{x^{2}-1-8x+4x+4}{\left(x+1\right)\left(x+4\right)}$$

Cumaisc téarmaí comhchosúla in: x^{2}-1-8x+4x+4.

$$\frac{x^{2}+3-4x}{\left(x+1\right)\left(x+4\right)}$$

Fairsingigh \left(x+1\right)\left(x+4\right)

$$\frac{x^{2}+3-4x}{x^{2}+5x+4}$$