Réitigh 3/2x-1-1/x+2

$$\frac { 3 } { 2 x - 1 } - \frac { 1 } { x + 2 }$$

Luacháil

$$\frac{x+7}{\left(2x-1\right)\left(x+2\right)}$$

Céimeanna gearra réitigh

Chun cothromóidí a shuimiú nó a dhealú, fairsingigh iad chun a n-ainmneoirí a mheaitseáil. Is é an t-iolrach is lú coitianta de 2x-1 agus x+2 ná \left(2x-1\right)\left(x+2\right). Méadaigh \frac{3}{2x-1} faoi \frac{x+2}{x+2}. Méadaigh \frac{1}{x+2} faoi \frac{2x-1}{2x-1}.

$$\frac{3\left(x+2\right)}{\left(2x-1\right)\left(x+2\right)}-\frac{2x-1}{\left(2x-1\right)\left(x+2\right)}$$

Tá an t-ainmneoir céanna ag \frac{3\left(x+2\right)}{\left(2x-1\right)\left(x+2\right)} agus \frac{2x-1}{\left(2x-1\right)\left(x+2\right)} agus, mar sin, is féidir iad a dhealú trína n-uimhreoirí a dhealú.

$$\frac{3\left(x+2\right)-\left(2x-1\right)}{\left(2x-1\right)\left(x+2\right)}$$

Déan iolrúcháin in 3\left(x+2\right)-\left(2x-1\right).

$$\frac{3x+6-2x+1}{\left(2x-1\right)\left(x+2\right)}$$

Cumaisc téarmaí comhchosúla in: 3x+6-2x+1.

$$\frac{x+7}{\left(2x-1\right)\left(x+2\right)}$$

Fairsingigh \left(2x-1\right)\left(x+2\right)

$$\frac{x+7}{2x^{2}+3x-2}$$

Difreálaigh w.r.t. x

$$-\frac{2x^{2}+28x+23}{4x^{4}+12x^{3}+x^{2}-12x+4}$$

Céimeanna ag Baint Úsáid as Riail na nDíorthach don Líon

Chun cothromóidí a shuimiú nó a dhealú, fairsingigh iad chun a n-ainmneoirí a mheaitseáil. Is é an t-iolrach is lú coitianta de 2x-1 agus x+2 ná \left(2x-1\right)\left(x+2\right). Méadaigh \frac{3}{2x-1} faoi \frac{x+2}{x+2}. Méadaigh \frac{1}{x+2} faoi \frac{2x-1}{2x-1}.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{3\left(x+2\right)}{\left(2x-1\right)\left(x+2\right)}-\frac{2x-1}{\left(2x-1\right)\left(x+2\right)})$$

Tá an t-ainmneoir céanna ag \frac{3\left(x+2\right)}{\left(2x-1\right)\left(x+2\right)} agus \frac{2x-1}{\left(2x-1\right)\left(x+2\right)} agus, mar sin, is féidir iad a dhealú trína n-uimhreoirí a dhealú.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{3\left(x+2\right)-\left(2x-1\right)}{\left(2x-1\right)\left(x+2\right)})$$

Déan iolrúcháin in 3\left(x+2\right)-\left(2x-1\right).

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{3x+6-2x+1}{\left(2x-1\right)\left(x+2\right)})$$

Cumaisc téarmaí comhchosúla in: 3x+6-2x+1.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{x+7}{\left(2x-1\right)\left(x+2\right)})$$

Cuir an t-airí dáileacháin i bhfeidhm trí gach téarma de 2x-1 a iolrú faoi gach téarma de x+2.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{x+7}{2x^{2}+4x-x-2})$$

Comhcheangail 4x agus -x chun 3x a fháil.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{x+7}{2x^{2}+3x-2})$$

Do dhá fheidhm indifreáilte ar bith, is ionann díorthach líon an dá fheidhme agus an t-ainmneoir méadaithe faoi dhíorthach an uimhreora lúide an t-uimhreoir méadaithe faoi dhíorthach an ainmneora, agus iad ar fad roinnte faoin ainmneoir cearnaithe.

$$\frac{\left(2x^{2}+3x^{1}-2\right)\frac{\mathrm{d}}{\mathrm{d}x}(x^{1}+7)-\left(x^{1}+7\right)\frac{\mathrm{d}}{\mathrm{d}x}(2x^{2}+3x^{1}-2)}{\left(2x^{2}+3x^{1}-2\right)^{2}}$$

Is ionann díorthach iltéarmaigh agus suim dhíorthaigh a théarmaí. Is ionann díorthach téarma thairisigh agus 0. Is ionann díorthach ax^{n} agus nax^{n-1}.

$$\frac{\left(2x^{2}+3x^{1}-2\right)x^{1-1}-\left(x^{1}+7\right)\left(2\times 2x^{2-1}+3x^{1-1}\right)}{\left(2x^{2}+3x^{1}-2\right)^{2}}$$

Simpligh.

$$\frac{\left(2x^{2}+3x^{1}-2\right)x^{0}-\left(x^{1}+7\right)\left(4x^{1}+3x^{0}\right)}{\left(2x^{2}+3x^{1}-2\right)^{2}}$$

Méadaigh 2x^{2}+3x^{1}-2 faoi x^{0}.

$$\frac{2x^{2}x^{0}+3x^{1}x^{0}-2x^{0}-\left(x^{1}+7\right)\left(4x^{1}+3x^{0}\right)}{\left(2x^{2}+3x^{1}-2\right)^{2}}$$

Méadaigh x^{1}+7 faoi 4x^{1}+3x^{0}.

$$\frac{2x^{2}x^{0}+3x^{1}x^{0}-2x^{0}-\left(x^{1}\times 4x^{1}+x^{1}\times 3x^{0}+7\times 4x^{1}+7\times 3x^{0}\right)}{\left(2x^{2}+3x^{1}-2\right)^{2}}$$

Chun cumhachtaí an bhoinn chéanna a mhéadú, suimigh a n-easpónaint.

$$\frac{2x^{2}+3x^{1}-2x^{0}-\left(4x^{1+1}+3x^{1}+7\times 4x^{1}+7\times 3x^{0}\right)}{\left(2x^{2}+3x^{1}-2\right)^{2}}$$

Simpligh.

$$\frac{2x^{2}+3x^{1}-2x^{0}-\left(4x^{2}+3x^{1}+28x^{1}+21x^{0}\right)}{\left(2x^{2}+3x^{1}-2\right)^{2}}$$

Cuir téarmaí cosúla le chéile.

$$\frac{-2x^{2}-28x^{1}-23x^{0}}{\left(2x^{2}+3x^{1}-2\right)^{2}}$$

Do théarma ar bith t, t^{1}=t.

$$\frac{-2x^{2}-28x-23x^{0}}{\left(2x^{2}+3x-2\right)^{2}}$$

Do théarma ar bith t ach amháin 0, t^{0}=1.

$$\frac{-2x^{2}-28x-23}{\left(2x^{2}+3x-2\right)^{2}}$$