Réitigh 3/2x^4-1/x+2-x+10/2x^2-8=

$$\frac { 3 } { 2 x ^ { 4 } } - \frac { 1 } { x + 2 } - \frac { x + 10 } { 2 x ^ { 2 } - 8 } =$$

Luacháil

$$\frac{3\left(-x^{4}+x-2\right)}{2\left(x-2\right)x^{4}}$$

Céimeanna gearra réitigh

Chun cothromóidí a shuimiú nó a dhealú, fairsingigh iad chun a n-ainmneoirí a mheaitseáil. Is é an t-iolrach is lú coitianta de 2x^{4} agus x+2 ná 2\left(x+2\right)x^{4}. Méadaigh \frac{3}{2x^{4}} faoi \frac{x+2}{x+2}. Méadaigh \frac{1}{x+2} faoi \frac{2x^{4}}{2x^{4}}.

$$\frac{3\left(x+2\right)}{2\left(x+2\right)x^{4}}-\frac{2x^{4}}{2\left(x+2\right)x^{4}}-\frac{x+10}{2x^{2}-8}$$

Tá an t-ainmneoir céanna ag \frac{3\left(x+2\right)}{2\left(x+2\right)x^{4}} agus \frac{2x^{4}}{2\left(x+2\right)x^{4}} agus, mar sin, is féidir iad a dhealú trína n-uimhreoirí a dhealú.

$$\frac{3\left(x+2\right)-2x^{4}}{2\left(x+2\right)x^{4}}-\frac{x+10}{2x^{2}-8}$$

Déan iolrúcháin in 3\left(x+2\right)-2x^{4}.

$$\frac{3x+6-2x^{4}}{2\left(x+2\right)x^{4}}-\frac{x+10}{2x^{2}-8}$$

Fachtóirigh 2x^{2}-8.

$$\frac{3x+6-2x^{4}}{2\left(x+2\right)x^{4}}-\frac{x+10}{2\left(x-2\right)\left(x+2\right)}$$

Chun cothromóidí a shuimiú nó a dhealú, fairsingigh iad chun a n-ainmneoirí a mheaitseáil. Is é an t-iolrach is lú coitianta de 2\left(x+2\right)x^{4} agus 2\left(x-2\right)\left(x+2\right) ná 2\left(x-2\right)\left(x+2\right)x^{4}. Méadaigh \frac{3x+6-2x^{4}}{2\left(x+2\right)x^{4}} faoi \frac{x-2}{x-2}. Méadaigh \frac{x+10}{2\left(x-2\right)\left(x+2\right)} faoi \frac{x^{4}}{x^{4}}.

$$\frac{\left(3x+6-2x^{4}\right)\left(x-2\right)}{2\left(x-2\right)\left(x+2\right)x^{4}}-\frac{\left(x+10\right)x^{4}}{2\left(x-2\right)\left(x+2\right)x^{4}}$$

Tá an t-ainmneoir céanna ag \frac{\left(3x+6-2x^{4}\right)\left(x-2\right)}{2\left(x-2\right)\left(x+2\right)x^{4}} agus \frac{\left(x+10\right)x^{4}}{2\left(x-2\right)\left(x+2\right)x^{4}} agus, mar sin, is féidir iad a dhealú trína n-uimhreoirí a dhealú.

$$\frac{\left(3x+6-2x^{4}\right)\left(x-2\right)-\left(x+10\right)x^{4}}{2\left(x-2\right)\left(x+2\right)x^{4}}$$

Déan iolrúcháin in \left(3x+6-2x^{4}\right)\left(x-2\right)-\left(x+10\right)x^{4}.

$$\frac{3x^{2}-6x+6x-12-2x^{5}+4x^{4}-x^{5}-10x^{4}}{2\left(x-2\right)\left(x+2\right)x^{4}}$$

Cumaisc téarmaí comhchosúla in: 3x^{2}-6x+6x-12-2x^{5}+4x^{4}-x^{5}-10x^{4}.

$$\frac{3x^{2}-12-3x^{5}-6x^{4}}{2\left(x-2\right)\left(x+2\right)x^{4}}$$

Fachtóirigh na sloinn nach bhfuil fachtóirithe cheana in \frac{3x^{2}-12-3x^{5}-6x^{4}}{2\left(x-2\right)\left(x+2\right)x^{4}}.

$$\frac{3\left(x+2\right)\left(-x^{4}+x-2\right)}{2\left(x-2\right)\left(x+2\right)x^{4}}$$

Cealaigh x+2 mar uimhreoir agus ainmneoir.

$$\frac{3\left(-x^{4}+x-2\right)}{2\left(x-2\right)x^{4}}$$

Fairsingigh 2\left(x-2\right)x^{4}

$$\frac{3\left(-x^{4}+x-2\right)}{2x^{5}-4x^{4}}$$

Úsáid an t-airí dáileach chun 3 a mhéadú faoi -x^{4}+x-2.

$$\frac{-3x^{4}+3x-6}{2x^{5}-4x^{4}}$$

Fairsingigh

$$-\frac{3\left(x^{4}-x+2\right)}{2\left(x-2\right)x^{4}}$$

Céimeanna gearra réitigh

Chun cothromóidí a shuimiú nó a dhealú, fairsingigh iad chun a n-ainmneoirí a mheaitseáil. Is é an t-iolrach is lú coitianta de 2x^{4} agus x+2 ná 2\left(x+2\right)x^{4}. Méadaigh \frac{3}{2x^{4}} faoi \frac{x+2}{x+2}. Méadaigh \frac{1}{x+2} faoi \frac{2x^{4}}{2x^{4}}.

$$\frac{3\left(x+2\right)}{2\left(x+2\right)x^{4}}-\frac{2x^{4}}{2\left(x+2\right)x^{4}}-\frac{x+10}{2x^{2}-8}$$

Tá an t-ainmneoir céanna ag \frac{3\left(x+2\right)}{2\left(x+2\right)x^{4}} agus \frac{2x^{4}}{2\left(x+2\right)x^{4}} agus, mar sin, is féidir iad a dhealú trína n-uimhreoirí a dhealú.

$$\frac{3\left(x+2\right)-2x^{4}}{2\left(x+2\right)x^{4}}-\frac{x+10}{2x^{2}-8}$$

Déan iolrúcháin in 3\left(x+2\right)-2x^{4}.

$$\frac{3x+6-2x^{4}}{2\left(x+2\right)x^{4}}-\frac{x+10}{2x^{2}-8}$$

Fachtóirigh 2x^{2}-8.

$$\frac{3x+6-2x^{4}}{2\left(x+2\right)x^{4}}-\frac{x+10}{2\left(x-2\right)\left(x+2\right)}$$

Chun cothromóidí a shuimiú nó a dhealú, fairsingigh iad chun a n-ainmneoirí a mheaitseáil. Is é an t-iolrach is lú coitianta de 2\left(x+2\right)x^{4} agus 2\left(x-2\right)\left(x+2\right) ná 2\left(x-2\right)\left(x+2\right)x^{4}. Méadaigh \frac{3x+6-2x^{4}}{2\left(x+2\right)x^{4}} faoi \frac{x-2}{x-2}. Méadaigh \frac{x+10}{2\left(x-2\right)\left(x+2\right)} faoi \frac{x^{4}}{x^{4}}.

$$\frac{\left(3x+6-2x^{4}\right)\left(x-2\right)}{2\left(x-2\right)\left(x+2\right)x^{4}}-\frac{\left(x+10\right)x^{4}}{2\left(x-2\right)\left(x+2\right)x^{4}}$$

Tá an t-ainmneoir céanna ag \frac{\left(3x+6-2x^{4}\right)\left(x-2\right)}{2\left(x-2\right)\left(x+2\right)x^{4}} agus \frac{\left(x+10\right)x^{4}}{2\left(x-2\right)\left(x+2\right)x^{4}} agus, mar sin, is féidir iad a dhealú trína n-uimhreoirí a dhealú.

$$\frac{\left(3x+6-2x^{4}\right)\left(x-2\right)-\left(x+10\right)x^{4}}{2\left(x-2\right)\left(x+2\right)x^{4}}$$

Déan iolrúcháin in \left(3x+6-2x^{4}\right)\left(x-2\right)-\left(x+10\right)x^{4}.

$$\frac{3x^{2}-6x+6x-12-2x^{5}+4x^{4}-x^{5}-10x^{4}}{2\left(x-2\right)\left(x+2\right)x^{4}}$$

Cumaisc téarmaí comhchosúla in: 3x^{2}-6x+6x-12-2x^{5}+4x^{4}-x^{5}-10x^{4}.

$$\frac{3x^{2}-12-3x^{5}-6x^{4}}{2\left(x-2\right)\left(x+2\right)x^{4}}$$

Fachtóirigh na sloinn nach bhfuil fachtóirithe cheana in \frac{3x^{2}-12-3x^{5}-6x^{4}}{2\left(x-2\right)\left(x+2\right)x^{4}}.

$$\frac{3\left(x+2\right)\left(-x^{4}+x-2\right)}{2\left(x-2\right)\left(x+2\right)x^{4}}$$

Cealaigh x+2 mar uimhreoir agus ainmneoir.

$$\frac{3\left(-x^{4}+x-2\right)}{2\left(x-2\right)x^{4}}$$

Fairsingigh 2\left(x-2\right)x^{4}

$$\frac{3\left(-x^{4}+x-2\right)}{2x^{5}-4x^{4}}$$

Úsáid an t-airí dáileach chun 3 a mhéadú faoi -x^{4}+x-2.

$$\frac{-3x^{4}+3x-6}{2x^{5}-4x^{4}}$$