Luacháil
\frac{2\sqrt{21}}{9}-\frac{\sqrt{3}}{9}-\frac{4\sqrt{7}}{27}+\frac{2}{27}\approx 0.508010982
Roinn
Cóipeáladh go dtí an ghearrthaisce
\frac{3\sqrt{3}-2}{2\sqrt{7}+1}\times 1
Roinn 2\sqrt{7}-1 faoi 2\sqrt{7}-1 chun 1 a fháil.
\frac{\left(3\sqrt{3}-2\right)\left(2\sqrt{7}-1\right)}{\left(2\sqrt{7}+1\right)\left(2\sqrt{7}-1\right)}\times 1
Iolraigh an t-uimhreoir agus an t-ainmneoir faoi 2\sqrt{7}-1 chun ainmneoir \frac{3\sqrt{3}-2}{2\sqrt{7}+1} a thiontú in uimhir chóimheasta.
\frac{\left(3\sqrt{3}-2\right)\left(2\sqrt{7}-1\right)}{\left(2\sqrt{7}\right)^{2}-1^{2}}\times 1
Mar shampla \left(2\sqrt{7}+1\right)\left(2\sqrt{7}-1\right). Is féidir iolrúchán a athrú ó bhonn go dtí difríocht na gcearnóg ag úsáid na rialach seo: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.
\frac{\left(3\sqrt{3}-2\right)\left(2\sqrt{7}-1\right)}{2^{2}\left(\sqrt{7}\right)^{2}-1^{2}}\times 1
Fairsingigh \left(2\sqrt{7}\right)^{2}
\frac{\left(3\sqrt{3}-2\right)\left(2\sqrt{7}-1\right)}{4\left(\sqrt{7}\right)^{2}-1^{2}}\times 1
Ríomh cumhacht 2 de 2 agus faigh 4.
\frac{\left(3\sqrt{3}-2\right)\left(2\sqrt{7}-1\right)}{4\times 7-1^{2}}\times 1
Is é 7 uimhir chearnach \sqrt{7}.
\frac{\left(3\sqrt{3}-2\right)\left(2\sqrt{7}-1\right)}{28-1^{2}}\times 1
Méadaigh 4 agus 7 chun 28 a fháil.
\frac{\left(3\sqrt{3}-2\right)\left(2\sqrt{7}-1\right)}{28-1}\times 1
Ríomh cumhacht 1 de 2 agus faigh 1.
\frac{\left(3\sqrt{3}-2\right)\left(2\sqrt{7}-1\right)}{27}\times 1
Dealaigh 1 ó 28 chun 27 a fháil.
\frac{\left(3\sqrt{3}-2\right)\left(2\sqrt{7}-1\right)}{27}
Scríobh \frac{\left(3\sqrt{3}-2\right)\left(2\sqrt{7}-1\right)}{27}\times 1 mar chodán aonair.
\frac{6\sqrt{3}\sqrt{7}-3\sqrt{3}-4\sqrt{7}+2}{27}
Cuir an t-airí dáileacháin i bhfeidhm trí gach téarma de 3\sqrt{3}-2 a iolrú faoi gach téarma de 2\sqrt{7}-1.
\frac{6\sqrt{21}-3\sqrt{3}-4\sqrt{7}+2}{27}
Iolraigh na huimhreacha faoin bhfréamh cearnach chun \sqrt{3} agus \sqrt{7} a iolrú.
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Cothromóid chomhuaineach
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Teorainneacha
\lim _{x \rightarrow-3} \frac{x^{2}-9}{x^{2}+2 x-3}