Réitigh frac{2x+sqrt{5}}{2sqrt{5}}=x/2-4

$$\frac { 2 x + \sqrt { 5 } } { 2 \sqrt { 5 } } = \frac { x } { 2 } - 4$$

Réitigh do x.

$$x=18\sqrt{5}+45\approx 85.249223595$$

Céimeanna chun Cothromóidí Líneacha a Réiteach

Méadaigh an dá thaobh den chothromóid faoi 2.

$$\frac{1}{5}\times 5^{\frac{1}{2}}\left(2x+\sqrt{5}\right)=x-8$$

Úsáid an t-airí dáileach chun \frac{1}{5}\times 5^{\frac{1}{2}} a mhéadú faoi 2x+\sqrt{5}.

$$\frac{1}{5}\times 5^{\frac{1}{2}}\times 2x+\frac{1}{5}\times 5^{\frac{1}{2}}\sqrt{5}=x-8$$

Méadaigh \frac{1}{5} agus 2 chun \frac{2}{5} a fháil.

$$\frac{2}{5}\times 5^{\frac{1}{2}}x+\frac{1}{5}\times 5^{\frac{1}{2}}\sqrt{5}=x-8$$

Bain x ón dá thaobh.

$$\frac{2}{5}\times 5^{\frac{1}{2}}x+\frac{1}{5}\times 5^{\frac{1}{2}}\sqrt{5}-x=-8$$

Bain \frac{1}{5}\times 5^{\frac{1}{2}}\sqrt{5} ón dá thaobh.

$$\frac{2}{5}\times 5^{\frac{1}{2}}x-x=-8-\frac{1}{5}\times 5^{\frac{1}{2}}\sqrt{5}$$

Athordaigh na téarmaí.

$$\frac{2}{5}\sqrt{5}x-x=-8-\frac{1}{5}\sqrt{5}\sqrt{5}$$

Méadaigh \sqrt{5} agus \sqrt{5} chun 5 a fháil.

$$\frac{2}{5}\sqrt{5}x-x=-8-\frac{1}{5}\times 5$$

Cealaigh 5 agus 5.

$$\frac{2}{5}\sqrt{5}x-x=-8-1$$

Dealaigh 1 ó -8 chun -9 a fháil.

$$\frac{2}{5}\sqrt{5}x-x=-9$$

Comhcheangail na téarmaí ar fad ina bhfuil x.

$$\left(\frac{2}{5}\sqrt{5}-1\right)x=-9$$

Tá an chothromóid i bhfoirm chaighdeánach.

$$\left(\frac{2\sqrt{5}}{5}-1\right)x=-9$$

Roinn an dá thaobh faoi \frac{2}{5}\sqrt{5}-1.

$$\frac{\left(\frac{2\sqrt{5}}{5}-1\right)x}{\frac{2\sqrt{5}}{5}-1}=-\frac{9}{\frac{2\sqrt{5}}{5}-1}$$

Má roinntear é faoi \frac{2}{5}\sqrt{5}-1 cuirtear an iolrúchán faoi \frac{2}{5}\sqrt{5}-1 ar ceal.

$$x=-\frac{9}{\frac{2\sqrt{5}}{5}-1}$$

Roinn -9 faoi \frac{2}{5}\sqrt{5}-1.

$$x=18\sqrt{5}+45$$