Réitigh 10/x^2+6+9+2/x+3

$$\frac { 10 } { x ^ { 2 } + 6 + 9 } + \frac { 2 } { x + 3 }$$

Luacháil

$$\frac{2\left(x^{2}+5x+30\right)}{\left(x+3\right)\left(x^{2}+15\right)}$$

Céimeanna gearra réitigh

Suimigh 6 agus 9 chun 15 a fháil.

$$\frac{10}{x^{2}+15}+\frac{2}{x+3}$$

Chun cothromóidí a shuimiú nó a dhealú, fairsingigh iad chun a n-ainmneoirí a mheaitseáil. Is é an t-iolrach is lú coitianta de x^{2}+15 agus x+3 ná \left(x+3\right)\left(x^{2}+15\right). Méadaigh \frac{10}{x^{2}+15} faoi \frac{x+3}{x+3}. Méadaigh \frac{2}{x+3} faoi \frac{x^{2}+15}{x^{2}+15}.

$$\frac{10\left(x+3\right)}{\left(x+3\right)\left(x^{2}+15\right)}+\frac{2\left(x^{2}+15\right)}{\left(x+3\right)\left(x^{2}+15\right)}$$

Tá an t-ainmneoir céanna ag \frac{10\left(x+3\right)}{\left(x+3\right)\left(x^{2}+15\right)} agus \frac{2\left(x^{2}+15\right)}{\left(x+3\right)\left(x^{2}+15\right)} agus, mar sin, is féidir iad a shuimiú trína n-uimhreoirí a shuimiú.

$$\frac{10\left(x+3\right)+2\left(x^{2}+15\right)}{\left(x+3\right)\left(x^{2}+15\right)}$$

Déan iolrúcháin in 10\left(x+3\right)+2\left(x^{2}+15\right).

$$\frac{10x+30+2x^{2}+30}{\left(x+3\right)\left(x^{2}+15\right)}$$

Cumaisc téarmaí comhchosúla in: 10x+30+2x^{2}+30.

$$\frac{10x+60+2x^{2}}{\left(x+3\right)\left(x^{2}+15\right)}$$

Fairsingigh \left(x+3\right)\left(x^{2}+15\right)

$$\frac{10x+60+2x^{2}}{x^{3}+3x^{2}+15x+45}$$

Fachtóirigh

$$\frac{2\left(x^{2}+5x+30\right)}{\left(x+3\right)\left(x^{2}+15\right)}$$