Réitigh frac{(frac{sqrt{3}}{1})^{2}+4x(1/sqrt{2})^2+3x(2/sqrt{3})^2*5*0^2}{2+2-(sqrt{3})^2}

$$\frac { ( \frac { \sqrt { 3 } } { 1 } ) ^ { 2 } + 4 x ( \frac { 1 } { \sqrt { 2 } } ) ^ { 2 } + 3 x ( \frac { 2 } { \sqrt { 3 } } ) ^ { 2 } \times 5 \times 0 ^ { 2 } } { 2 + 2 - ( \sqrt { 3 } ) ^ { 2 } }$$

Luacháil

$$2x+3$$

Céimeanna Réitigh

Tugann aon rud a roinntear ar a haon é féin.

$$\frac{\left(\sqrt{3}\right)^{2}+4x\times \left(\frac{1}{\sqrt{2}}\right)^{2}+3\times 5x\times \left(\frac{2}{\sqrt{3}}\right)^{2}\times 0^{2}}{2+2-\left(\sqrt{3}\right)^{2}}$$

Is é 3 uimhir chearnach \sqrt{3}.

$$\frac{3+4x\times \left(\frac{1}{\sqrt{2}}\right)^{2}+3\times 5x\times \left(\frac{2}{\sqrt{3}}\right)^{2}\times 0^{2}}{2+2-\left(\sqrt{3}\right)^{2}}$$

Iolraigh an t-uimhreoir agus an t-ainmneoir faoi \sqrt{2} chun ainmneoir \frac{1}{\sqrt{2}} a thiontú in uimhir chóimheasta.

$$\frac{3+4x\times \left(\frac{\sqrt{2}}{\left(\sqrt{2}\right)^{2}}\right)^{2}+3\times 5x\times \left(\frac{2}{\sqrt{3}}\right)^{2}\times 0^{2}}{2+2-\left(\sqrt{3}\right)^{2}}$$

Is é 2 uimhir chearnach \sqrt{2}.

$$\frac{3+4x\times \left(\frac{\sqrt{2}}{2}\right)^{2}+3\times 5x\times \left(\frac{2}{\sqrt{3}}\right)^{2}\times 0^{2}}{2+2-\left(\sqrt{3}\right)^{2}}$$

Chun \frac{\sqrt{2}}{2} a iolrú i gcumhacht, iolraigh an t-uimhreoir agus an t-ainmneoir araon i gcumhacht agus déan iad a roinnt ansin.

$$\frac{3+4x\times \frac{\left(\sqrt{2}\right)^{2}}{2^{2}}+3\times 5x\times \left(\frac{2}{\sqrt{3}}\right)^{2}\times 0^{2}}{2+2-\left(\sqrt{3}\right)^{2}}$$

Scríobh 4\times \frac{\left(\sqrt{2}\right)^{2}}{2^{2}} mar chodán aonair.

$$\frac{3+\frac{4\left(\sqrt{2}\right)^{2}}{2^{2}}x+3\times 5x\times \left(\frac{2}{\sqrt{3}}\right)^{2}\times 0^{2}}{2+2-\left(\sqrt{3}\right)^{2}}$$

Méadaigh 3 agus 5 chun 15 a fháil.

$$\frac{3+\frac{4\left(\sqrt{2}\right)^{2}}{2^{2}}x+15x\times \left(\frac{2}{\sqrt{3}}\right)^{2}\times 0^{2}}{2+2-\left(\sqrt{3}\right)^{2}}$$

Iolraigh an t-uimhreoir agus an t-ainmneoir faoi \sqrt{3} chun ainmneoir \frac{2}{\sqrt{3}} a thiontú in uimhir chóimheasta.

$$\frac{3+\frac{4\left(\sqrt{2}\right)^{2}}{2^{2}}x+15x\times \left(\frac{2\sqrt{3}}{\left(\sqrt{3}\right)^{2}}\right)^{2}\times 0^{2}}{2+2-\left(\sqrt{3}\right)^{2}}$$

Is é 3 uimhir chearnach \sqrt{3}.

$$\frac{3+\frac{4\left(\sqrt{2}\right)^{2}}{2^{2}}x+15x\times \left(\frac{2\sqrt{3}}{3}\right)^{2}\times 0^{2}}{2+2-\left(\sqrt{3}\right)^{2}}$$

Chun \frac{2\sqrt{3}}{3} a iolrú i gcumhacht, iolraigh an t-uimhreoir agus an t-ainmneoir araon i gcumhacht agus déan iad a roinnt ansin.

$$\frac{3+\frac{4\left(\sqrt{2}\right)^{2}}{2^{2}}x+15x\times \frac{\left(2\sqrt{3}\right)^{2}}{3^{2}}\times 0^{2}}{2+2-\left(\sqrt{3}\right)^{2}}$$

Ríomh cumhacht 0 de 2 agus faigh 0.

$$\frac{3+\frac{4\left(\sqrt{2}\right)^{2}}{2^{2}}x+15x\times \frac{\left(2\sqrt{3}\right)^{2}}{3^{2}}\times 0}{2+2-\left(\sqrt{3}\right)^{2}}$$

Méadaigh 15 agus 0 chun 0 a fháil.

$$\frac{3+\frac{4\left(\sqrt{2}\right)^{2}}{2^{2}}x+0x\times \frac{\left(2\sqrt{3}\right)^{2}}{3^{2}}}{2+2-\left(\sqrt{3}\right)^{2}}$$

Fairsingigh \left(2\sqrt{3}\right)^{2}

$$\frac{3+\frac{4\left(\sqrt{2}\right)^{2}}{2^{2}}x+0x\times \frac{2^{2}\left(\sqrt{3}\right)^{2}}{3^{2}}}{2+2-\left(\sqrt{3}\right)^{2}}$$

Ríomh cumhacht 2 de 2 agus faigh 4.

$$\frac{3+\frac{4\left(\sqrt{2}\right)^{2}}{2^{2}}x+0x\times \frac{4\left(\sqrt{3}\right)^{2}}{3^{2}}}{2+2-\left(\sqrt{3}\right)^{2}}$$

Is é 3 uimhir chearnach \sqrt{3}.

$$\frac{3+\frac{4\left(\sqrt{2}\right)^{2}}{2^{2}}x+0x\times \frac{4\times 3}{3^{2}}}{2+2-\left(\sqrt{3}\right)^{2}}$$

Méadaigh 4 agus 3 chun 12 a fháil.

$$\frac{3+\frac{4\left(\sqrt{2}\right)^{2}}{2^{2}}x+0x\times \frac{12}{3^{2}}}{2+2-\left(\sqrt{3}\right)^{2}}$$

Ríomh cumhacht 3 de 2 agus faigh 9.

$$\frac{3+\frac{4\left(\sqrt{2}\right)^{2}}{2^{2}}x+0x\times \frac{12}{9}}{2+2-\left(\sqrt{3}\right)^{2}}$$

Laghdaigh an codán \frac{12}{9} chuig na téarmaí is ísle trí 3 a bhaint agus a chealú.

$$\frac{3+\frac{4\left(\sqrt{2}\right)^{2}}{2^{2}}x+0x\times \frac{4}{3}}{2+2-\left(\sqrt{3}\right)^{2}}$$

Méadaigh 0 agus \frac{4}{3} chun 0 a fháil.

$$\frac{3+\frac{4\left(\sqrt{2}\right)^{2}}{2^{2}}x+0x}{2+2-\left(\sqrt{3}\right)^{2}}$$

Is ionann rud ar bith méadaithe faoi nialas agus nialas.

$$\frac{3+\frac{4\left(\sqrt{2}\right)^{2}}{2^{2}}x+0}{2+2-\left(\sqrt{3}\right)^{2}}$$

Suimigh 3 agus 0 chun 3 a fháil.

$$\frac{3+\frac{4\left(\sqrt{2}\right)^{2}}{2^{2}}x}{2+2-\left(\sqrt{3}\right)^{2}}$$

Is é 2 uimhir chearnach \sqrt{2}.

$$\frac{3+\frac{4\times 2}{2^{2}}x}{2+2-\left(\sqrt{3}\right)^{2}}$$

Méadaigh 4 agus 2 chun 8 a fháil.

$$\frac{3+\frac{8}{2^{2}}x}{2+2-\left(\sqrt{3}\right)^{2}}$$

Ríomh cumhacht 2 de 2 agus faigh 4.

$$\frac{3+\frac{8}{4}x}{2+2-\left(\sqrt{3}\right)^{2}}$$

Roinn 8 faoi 4 chun 2 a fháil.

$$\frac{3+2x}{2+2-\left(\sqrt{3}\right)^{2}}$$

Suimigh 2 agus 2 chun 4 a fháil.

$$\frac{3+2x}{4-\left(\sqrt{3}\right)^{2}}$$

Is é 3 uimhir chearnach \sqrt{3}.

$$\frac{3+2x}{4-3}$$

Dealaigh 3 ó 4 chun 1 a fháil.

$$\frac{3+2x}{1}$$

Tugann aon rud a roinntear ar a haon é féin.

$$3+2x$$

Fachtóirigh

$$2x+3$$