Réitigh frac{(frac{sqrt{3}}{1})^{2}+4*(1/sqrt{2})^2+3*(2/sqrt{3})^2+5*0^2}{2+2-(sqrt{3})^2}

$$\frac { ( \frac { \sqrt { 3 } } { 1 } ) ^ { 2 } + 4 \times ( \frac { 1 } { \sqrt { 2 } } ) ^ { 2 } + 3 \times ( \frac { 2 } { \sqrt { 3 } } ) ^ { 2 } + 5 \times 0 ^ { 2 } } { 2 + 2 - ( \sqrt { 3 } ) ^ { 2 } }$$

Luacháil

$$9$$

Céimeanna Réitigh

Tugann aon rud a roinntear ar a haon é féin.

$$\frac{\left(\sqrt{3}\right)^{2}+4\times \left(\frac{1}{\sqrt{2}}\right)^{2}+3\times \left(\frac{2}{\sqrt{3}}\right)^{2}+5\times 0^{2}}{2+2-\left(\sqrt{3}\right)^{2}}$$

Is é 3 uimhir chearnach \sqrt{3}.

$$\frac{3+4\times \left(\frac{1}{\sqrt{2}}\right)^{2}+3\times \left(\frac{2}{\sqrt{3}}\right)^{2}+5\times 0^{2}}{2+2-\left(\sqrt{3}\right)^{2}}$$

Iolraigh an t-uimhreoir agus an t-ainmneoir faoi \sqrt{2} chun ainmneoir \frac{1}{\sqrt{2}} a thiontú in uimhir chóimheasta.

$$\frac{3+4\times \left(\frac{\sqrt{2}}{\left(\sqrt{2}\right)^{2}}\right)^{2}+3\times \left(\frac{2}{\sqrt{3}}\right)^{2}+5\times 0^{2}}{2+2-\left(\sqrt{3}\right)^{2}}$$

Is é 2 uimhir chearnach \sqrt{2}.

$$\frac{3+4\times \left(\frac{\sqrt{2}}{2}\right)^{2}+3\times \left(\frac{2}{\sqrt{3}}\right)^{2}+5\times 0^{2}}{2+2-\left(\sqrt{3}\right)^{2}}$$

Chun \frac{\sqrt{2}}{2} a iolrú i gcumhacht, iolraigh an t-uimhreoir agus an t-ainmneoir araon i gcumhacht agus déan iad a roinnt ansin.

$$\frac{3+4\times \frac{\left(\sqrt{2}\right)^{2}}{2^{2}}+3\times \left(\frac{2}{\sqrt{3}}\right)^{2}+5\times 0^{2}}{2+2-\left(\sqrt{3}\right)^{2}}$$

Scríobh 4\times \frac{\left(\sqrt{2}\right)^{2}}{2^{2}} mar chodán aonair.

$$\frac{3+\frac{4\left(\sqrt{2}\right)^{2}}{2^{2}}+3\times \left(\frac{2}{\sqrt{3}}\right)^{2}+5\times 0^{2}}{2+2-\left(\sqrt{3}\right)^{2}}$$

Iolraigh an t-uimhreoir agus an t-ainmneoir faoi \sqrt{3} chun ainmneoir \frac{2}{\sqrt{3}} a thiontú in uimhir chóimheasta.

$$\frac{3+\frac{4\left(\sqrt{2}\right)^{2}}{2^{2}}+3\times \left(\frac{2\sqrt{3}}{\left(\sqrt{3}\right)^{2}}\right)^{2}+5\times 0^{2}}{2+2-\left(\sqrt{3}\right)^{2}}$$

Is é 3 uimhir chearnach \sqrt{3}.

$$\frac{3+\frac{4\left(\sqrt{2}\right)^{2}}{2^{2}}+3\times \left(\frac{2\sqrt{3}}{3}\right)^{2}+5\times 0^{2}}{2+2-\left(\sqrt{3}\right)^{2}}$$

Chun \frac{2\sqrt{3}}{3} a iolrú i gcumhacht, iolraigh an t-uimhreoir agus an t-ainmneoir araon i gcumhacht agus déan iad a roinnt ansin.

$$\frac{3+\frac{4\left(\sqrt{2}\right)^{2}}{2^{2}}+3\times \frac{\left(2\sqrt{3}\right)^{2}}{3^{2}}+5\times 0^{2}}{2+2-\left(\sqrt{3}\right)^{2}}$$

Scríobh 3\times \frac{\left(2\sqrt{3}\right)^{2}}{3^{2}} mar chodán aonair.

$$\frac{3+\frac{4\left(\sqrt{2}\right)^{2}}{2^{2}}+\frac{3\times \left(2\sqrt{3}\right)^{2}}{3^{2}}+5\times 0^{2}}{2+2-\left(\sqrt{3}\right)^{2}}$$

Cealaigh 3 mar uimhreoir agus ainmneoir.

$$\frac{3+\frac{4\left(\sqrt{2}\right)^{2}}{2^{2}}+\frac{\left(2\sqrt{3}\right)^{2}}{3}+5\times 0^{2}}{2+2-\left(\sqrt{3}\right)^{2}}$$

Ríomh cumhacht 0 de 2 agus faigh 0.

$$\frac{3+\frac{4\left(\sqrt{2}\right)^{2}}{2^{2}}+\frac{\left(2\sqrt{3}\right)^{2}}{3}+5\times 0}{2+2-\left(\sqrt{3}\right)^{2}}$$

Méadaigh 5 agus 0 chun 0 a fháil.

$$\frac{3+\frac{4\left(\sqrt{2}\right)^{2}}{2^{2}}+\frac{\left(2\sqrt{3}\right)^{2}}{3}+0}{2+2-\left(\sqrt{3}\right)^{2}}$$

Suimigh 3 agus 0 chun 3 a fháil.

$$\frac{3+\frac{4\left(\sqrt{2}\right)^{2}}{2^{2}}+\frac{\left(2\sqrt{3}\right)^{2}}{3}}{2+2-\left(\sqrt{3}\right)^{2}}$$

Fairsingigh \left(2\sqrt{3}\right)^{2}

$$\frac{3+\frac{4\left(\sqrt{2}\right)^{2}}{2^{2}}+\frac{2^{2}\left(\sqrt{3}\right)^{2}}{3}}{2+2-\left(\sqrt{3}\right)^{2}}$$

Ríomh cumhacht 2 de 2 agus faigh 4.

$$\frac{3+\frac{4\left(\sqrt{2}\right)^{2}}{2^{2}}+\frac{4\left(\sqrt{3}\right)^{2}}{3}}{2+2-\left(\sqrt{3}\right)^{2}}$$

Is é 3 uimhir chearnach \sqrt{3}.

$$\frac{3+\frac{4\left(\sqrt{2}\right)^{2}}{2^{2}}+\frac{4\times 3}{3}}{2+2-\left(\sqrt{3}\right)^{2}}$$

Méadaigh 4 agus 3 chun 12 a fháil.

$$\frac{3+\frac{4\left(\sqrt{2}\right)^{2}}{2^{2}}+\frac{12}{3}}{2+2-\left(\sqrt{3}\right)^{2}}$$

Roinn 12 faoi 3 chun 4 a fháil.

$$\frac{3+\frac{4\left(\sqrt{2}\right)^{2}}{2^{2}}+4}{2+2-\left(\sqrt{3}\right)^{2}}$$

Suimigh 3 agus 4 chun 7 a fháil.

$$\frac{7+\frac{4\left(\sqrt{2}\right)^{2}}{2^{2}}}{2+2-\left(\sqrt{3}\right)^{2}}$$

Is é 2 uimhir chearnach \sqrt{2}.

$$\frac{7+\frac{4\times 2}{2^{2}}}{2+2-\left(\sqrt{3}\right)^{2}}$$

Méadaigh 4 agus 2 chun 8 a fháil.

$$\frac{7+\frac{8}{2^{2}}}{2+2-\left(\sqrt{3}\right)^{2}}$$

Ríomh cumhacht 2 de 2 agus faigh 4.

$$\frac{7+\frac{8}{4}}{2+2-\left(\sqrt{3}\right)^{2}}$$

Roinn 8 faoi 4 chun 2 a fháil.

$$\frac{7+2}{2+2-\left(\sqrt{3}\right)^{2}}$$

Suimigh 7 agus 2 chun 9 a fháil.

$$\frac{9}{2+2-\left(\sqrt{3}\right)^{2}}$$

Suimigh 2 agus 2 chun 4 a fháil.

$$\frac{9}{4-\left(\sqrt{3}\right)^{2}}$$

Is é 3 uimhir chearnach \sqrt{3}.

$$\frac{9}{4-3}$$

Dealaigh 3 ó 4 chun 1 a fháil.

$$\frac{9}{1}$$

Tugann aon rud a roinntear ar a haon é féin.

$$9$$

Fachtóirigh

$$3^{2}$$