Réitigh alpha^2+beta^2=(alpha+beta)^2-2

$$\alpha ^ { 2 } + \beta ^ { 2 } = ( \alpha + \beta ) ^ { 2 } - 2$$

Réitigh do α.

$$\alpha =\frac{1}{\beta }$$

$$\beta \neq 0$$

Céimeanna chun Cothromóidí Líneacha a Réiteach

Úsáid an teoirim dhéthéarmach \left(a+b\right)^{2}=a^{2}+2ab+b^{2} chun \left(\alpha +\beta \right)^{2} a leathnú.

$$\alpha ^{2}+\beta ^{2}=\alpha ^{2}+2\alpha \beta +\beta ^{2}-2$$

Bain \alpha ^{2} ón dá thaobh.

$$\alpha ^{2}+\beta ^{2}-\alpha ^{2}=2\alpha \beta +\beta ^{2}-2$$

Comhcheangail \alpha ^{2} agus -\alpha ^{2} chun 0 a fháil.

$$\beta ^{2}=2\alpha \beta +\beta ^{2}-2$$

Athraigh na taobhanna ionas go mbeidh na téarmaí inathraitheacha ar fad ar an taobh clé.

$$2\alpha \beta +\beta ^{2}-2=\beta ^{2}$$

Bain \beta ^{2} ón dá thaobh.

$$2\alpha \beta -2=\beta ^{2}-\beta ^{2}$$

Comhcheangail \beta ^{2} agus -\beta ^{2} chun 0 a fháil.

$$2\alpha \beta -2=0$$

Cuir 2 leis an dá thaobh. Is ionann rud ar bith móide nialas agus a shuim féin.

$$2\alpha \beta =2$$

Tá an chothromóid i bhfoirm chaighdeánach.

$$2\beta \alpha =2$$

Roinn an dá thaobh faoi 2\beta .

$$\frac{2\beta \alpha }{2\beta }=\frac{2}{2\beta }$$

Má roinntear é faoi 2\beta cuirtear an iolrúchán faoi 2\beta ar ceal.

$$\alpha =\frac{2}{2\beta }$$

Roinn 2 faoi 2\beta .

$$\alpha =\frac{1}{\beta }$$

Réitigh do β.

$$\beta =\frac{1}{\alpha }$$

$$\alpha \neq 0$$

Céimeanna chun Cothromóidí Líneacha a Réiteach

Úsáid an teoirim dhéthéarmach \left(a+b\right)^{2}=a^{2}+2ab+b^{2} chun \left(\alpha +\beta \right)^{2} a leathnú.

$$\alpha ^{2}+\beta ^{2}=\alpha ^{2}+2\alpha \beta +\beta ^{2}-2$$

Bain 2\alpha \beta ón dá thaobh.

$$\alpha ^{2}+\beta ^{2}-2\alpha \beta =\alpha ^{2}+\beta ^{2}-2$$

Bain \beta ^{2} ón dá thaobh.

$$\alpha ^{2}+\beta ^{2}-2\alpha \beta -\beta ^{2}=\alpha ^{2}-2$$

Comhcheangail \beta ^{2} agus -\beta ^{2} chun 0 a fháil.

$$\alpha ^{2}-2\alpha \beta =\alpha ^{2}-2$$

Bain \alpha ^{2} ón dá thaobh.

$$-2\alpha \beta =\alpha ^{2}-2-\alpha ^{2}$$

Comhcheangail \alpha ^{2} agus -\alpha ^{2} chun 0 a fháil.

$$-2\alpha \beta =-2$$

Tá an chothromóid i bhfoirm chaighdeánach.

$$\left(-2\alpha \right)\beta =-2$$

Roinn an dá thaobh faoi -2\alpha .

$$\frac{\left(-2\alpha \right)\beta }{-2\alpha }=-\frac{2}{-2\alpha }$$

Má roinntear é faoi -2\alpha cuirtear an iolrúchán faoi -2\alpha ar ceal.

$$\beta =-\frac{2}{-2\alpha }$$

Roinn -2 faoi -2\alpha .

$$\beta =\frac{1}{\alpha }$$