Réitigh =-[2/10b_{2}(2/10)+8/10log_{2}(8/10)]

$$= - [ \frac { 2 } { 10 } b _ { 2 } ( \frac { 2 } { 10 } ) + \frac { 8 } { 10 } \log _ { 2 } ( \frac { 8 } { 10 } ) ]$$

Luacháil

$$-\frac{b_{2}}{25}+\frac{4\log_{2}\left(5\right)}{5}-\frac{8}{5}$$

Céimeanna Réitigh

Méadaigh \frac{2}{10} agus \frac{2}{10} chun \left(\frac{2}{10}\right)^{2} a fháil.

$$-\left(\left(\frac{2}{10}\right)^{2}b_{2}+\frac{8}{10}\log_{2}\left(\frac{8}{10}\right)\right)$$

Laghdaigh an codán \frac{2}{10} chuig na téarmaí is ísle trí 2 a bhaint agus a chealú.

$$-\left(\left(\frac{1}{5}\right)^{2}b_{2}+\frac{8}{10}\log_{2}\left(\frac{8}{10}\right)\right)$$

Ríomh cumhacht \frac{1}{5} de 2 agus faigh \frac{1}{25}.

$$-\left(\frac{1}{25}b_{2}+\frac{8}{10}\log_{2}\left(\frac{8}{10}\right)\right)$$

Laghdaigh an codán \frac{8}{10} chuig na téarmaí is ísle trí 2 a bhaint agus a chealú.

$$-\left(\frac{1}{25}b_{2}+\frac{4}{5}\log_{2}\left(\frac{8}{10}\right)\right)$$

Laghdaigh an codán \frac{8}{10} chuig na téarmaí is ísle trí 2 a bhaint agus a chealú.

$$-\left(\frac{1}{25}b_{2}+\frac{4}{5}\log_{2}\left(\frac{4}{5}\right)\right)$$

Chun an mhalairt ar \frac{1}{25}b_{2}+\frac{4}{5}\log_{2}\left(\frac{4}{5}\right) a aimsiú, aimsigh an mhalairt ar gach téarma.

$$-\frac{1}{25}b_{2}-\frac{4}{5}\log_{2}\left(\frac{4}{5}\right)$$

Fachtóirigh

$$\frac{-b_{2}+20\log_{2}\left(5\right)-40}{25}$$

Céimeanna Réitigh

Mar shampla \frac{1}{5}\times \frac{1}{5}b_{2}+\frac{4}{5}\ln(\frac{4}{5})\ln(2)^{-1}. Fág \frac{1}{25} as an áireamh.

$$\frac{b_{2}+20\log_{2}\left(\frac{4}{5}\right)}{25}$$

Athscríobh an slonn iomlán fachtóirithe. Simpligh.

$$-\frac{b_{2}+20\log_{2}\left(\frac{4}{5}\right)}{25}$$