Réitigh =22000/(1+r)^2-18000

$$= \frac { 22000 } { ( 1 + r ) ^ { 2 } } - 18000$$

Luacháil

$$\frac{2000\left(2-18r-9r^{2}\right)}{\left(r+1\right)^{2}}$$

Céimeanna gearra réitigh

Chun cothromóidí a shuimiú nó a dhealú, fairsingigh iad chun a n-ainmneoirí a mheaitseáil. Méadaigh 18000 faoi \frac{\left(1+r\right)^{2}}{\left(1+r\right)^{2}}.

$$\frac{22000}{\left(1+r\right)^{2}}-\frac{18000\left(1+r\right)^{2}}{\left(1+r\right)^{2}}$$

Tá an t-ainmneoir céanna ag \frac{22000}{\left(1+r\right)^{2}} agus \frac{18000\left(1+r\right)^{2}}{\left(1+r\right)^{2}} agus, mar sin, is féidir iad a dhealú trína n-uimhreoirí a dhealú.

$$\frac{22000-18000\left(1+r\right)^{2}}{\left(1+r\right)^{2}}$$

Déan iolrúcháin in 22000-18000\left(1+r\right)^{2}.

$$\frac{22000-18000-36000r-18000r^{2}}{\left(1+r\right)^{2}}$$

Cumaisc téarmaí comhchosúla in: 22000-18000-36000r-18000r^{2}.

$$\frac{4000-36000r-18000r^{2}}{\left(1+r\right)^{2}}$$

Fairsingigh \left(1+r\right)^{2}

$$\frac{4000-36000r-18000r^{2}}{r^{2}+2r+1}$$

Fairsingigh

$$-\frac{2000\left(9r^{2}+18r-2\right)}{\left(r+1\right)^{2}}$$

Céimeanna gearra réitigh

Chun cothromóidí a shuimiú nó a dhealú, fairsingigh iad chun a n-ainmneoirí a mheaitseáil. Méadaigh 18000 faoi \frac{\left(1+r\right)^{2}}{\left(1+r\right)^{2}}.

$$\frac{22000}{\left(1+r\right)^{2}}-\frac{18000\left(1+r\right)^{2}}{\left(1+r\right)^{2}}$$

Tá an t-ainmneoir céanna ag \frac{22000}{\left(1+r\right)^{2}} agus \frac{18000\left(1+r\right)^{2}}{\left(1+r\right)^{2}} agus, mar sin, is féidir iad a dhealú trína n-uimhreoirí a dhealú.

$$\frac{22000-18000\left(1+r\right)^{2}}{\left(1+r\right)^{2}}$$

Déan iolrúcháin in 22000-18000\left(1+r\right)^{2}.

$$\frac{22000-18000-36000r-18000r^{2}}{\left(1+r\right)^{2}}$$

Cumaisc téarmaí comhchosúla in: 22000-18000-36000r-18000r^{2}.

$$\frac{4000-36000r-18000r^{2}}{\left(1+r\right)^{2}}$$

Fairsingigh \left(1+r\right)^{2}

$$\frac{4000-36000r-18000r^{2}}{r^{2}+2r+1}$$