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Factoriser

a (b + c)

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Évaluer

a (b + c)

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Quiz

a b + a c

Problèmes similaires dans la recherche Web

How do you factor

5 a b + 6 a

https://socratic.org/questions/how-do-you-factor-5ab-6a

a \cdot (5 b + 6)

Explanation: Expression

= 5 a b + 6 a

= a \cdot (5 b + 6)

Hence, the factors of the ...

a

b

c

be integers. Prove that if

4 ∣ (a + b c)

6 ∣ (b + a c)

2 ∣ (a^{2} - b^{2})

https://math.stackexchange.com/questions/2443540/let-a-b-and-c-be-integers-prove-that-if-4abc-and-6bac-then

4 ∣ (a + b c)

a + b c = 4 k \to c = \frac{4 k - a}{b}

6 ∣ (b + a c)

b + a c = 6 h

c

b + a \frac{4 k - a}{b} = 6 h

b^{2} + 4 a k - a^{2} = 6 b h

a^{2} - b^{2} = 2 (2 a k - 3 b h)

Which means that

2 ∣ (a^{2} - b^{2})

In standard orthic configuration , find AB + AC. [closed]

https://math.stackexchange.com/questions/2172641/in-standard-orthic-configuration-find-ab-ac

∠ B F C = ∠ B E C = 9 0^{\circ}

B F E C

is cyclic and the center of their circle is

A^{'}

∠ F A^{'} E = 3 0^{\circ}

∠ F B E = ∠ F C E = 1 5^{\circ}

∠ B A D = 2 φ

Can't simplify this boolean expression

https://math.stackexchange.com/questions/1534246/cant-simplify-this-boolean-expression

Question regarding matrices and determinants.

https://math.stackexchange.com/questions/1196820/question-regarding-matrices-and-determinants

This is what I get:

B - I = A^{- 1} A (B - I) = A^{- 1} (A B - A) = A^{- 1} B A .

Taking determinants,

∣ B - I ∣ = ∣ B ∣,

and joining it with what you got, you are done. Notice that what you did is correct, since

B + I = (B + I) A A^{- 1} = (B A + A) A^{- 1} = A B A^{- 1} .

Absolute value property proof

https://math.stackexchange.com/questions/2332463/absolute-value-property-proof

Using your idea you can conclude

(b - a) (b + a) > 0

b - a, b + a > 0

b - a, b + a < 0

. In the first case you have

a < b

a > - b

∣ a ∣ < ∣ b ∣

. In the second you have

b < a

b < - a

∣ b ∣ > ∣ a ∣

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Copié dans le Presse-papiers

a\left(b+c\right)

Exclure a.

Exemples

Équation du second degré

x^{2} - 4 x - 5 = 0

4 sin θ cos θ = 2 sin θ

Équation linéaire

y = 3 x + 4

699 * 533

[2534] [2 - 1 0135]

Équation simultanée

{8 x + 2 y = 46 7 x + 3 y = 47

Différenciation

\frac{d}{d x} \frac{( 3 x ^{2} - 2 )}{( x - 5 )}

\int_{0}^{1} x e^{- x^{2}} d x

x \to - 3 lim \frac{x ^{2} - 9}{x ^{2} + 2 x - 3}