Lutasin ang y=x^3+3x^2-x-3/x^2-1.

$$y = \frac { x ^ { 3 } + 3 x ^ { 2 } - x - 3 } { x ^ { 2 } - 1 } .$$

I-solve ang y (complex solution)

$$y=x+3$$

$$x\neq -1\text{ and }x\neq 1$$

Maiikling Hakbang sa Solution

I-factor ang mga expression na hindi pa na-factor sa \frac{x^{3}+3x^{2}-x-3}{x^{2}-1}.

$$y=\frac{\left(x-1\right)\left(x+1\right)\left(x+3\right)}{\left(x-1\right)\left(x+1\right)}$$

I-cancel out ang \left(x-1\right)\left(x+1\right) sa parehong numerator at denominator.

$$y=x+3$$

I-solve ang y

$$y=x+3$$

$$|x|\neq 1$$

Maiikling Hakbang sa Solution

I-factor ang mga expression na hindi pa na-factor sa \frac{x^{3}+3x^{2}-x-3}{x^{2}-1}.

$$y=\frac{\left(x-1\right)\left(x+1\right)\left(x+3\right)}{\left(x-1\right)\left(x+1\right)}$$

I-cancel out ang \left(x-1\right)\left(x+1\right) sa parehong numerator at denominator.

$$y=x+3$$

I-solve ang x (complex solution)

$$x=y-3$$

$$y\neq 2\text{ and }y\neq 4$$

I-solve ang x

$$x=y-3$$

$$y\neq 4\text{ and }y\neq 2$$