Lutasin ang x^{(5+a)^2}*x^(5-a)^2=x^40

$$x ^ { ( 5 + a ) ^ { 2 } } \times x ^ { ( 5 - a ) ^ { 2 } } = x ^ { 40 }$$

I-solve ang a

$$\left\{\begin{matrix}a\in \mathrm{R}\text{, }&\left(x=-1\text{ and }Numerator(2a^{2}+50)\text{bmod}2=0\text{ and }Denominator(\left(5-a\right)^{2})\text{bmod}2=1\text{ and }Denominator(\left(a+5\right)^{2})\text{bmod}2=1\right)\text{ or }x=1\\a\in \mathrm{R}\setminus 5,-5\text{, }&x=0\end{matrix}\right.$$

I-solve ang x

$$\left\{\begin{matrix}\\x=1\text{, }&\text{unconditionally}\\x=0\text{, }&|a|\neq 5\\x=-1\text{, }&Numerator(2a^{2}+50)\text{bmod}2=0\text{ and }Denominator(\left(a+5\right)^{2})\text{bmod}2=1\text{ and }Denominator(\left(5-a\right)^{2})\text{bmod}2=1\end{matrix}\right.$$