Lutasin ang g(y)=y^2-y-12/9y^3-5y^2*81y^3-25y/4y-16

$$g ( y ) = \frac { y ^ { 2 } - y - 12 } { 9 y ^ { 3 } - 5 y ^ { 2 } } \cdot \frac { 81 y ^ { 3 } - 25 y } { 4 y - 16 }$$

I-evaluate

$$\frac{9y}{4}+8+\frac{15}{4y}$$

Maiikling Hakbang sa Solution

I-multiply ang \frac{y^{2}-y-12}{9y^{3}-5y^{2}} sa \frac{81y^{3}-25y}{4y-16} sa pamamagitan ng pag-multiply ng numerator sa numerator at denominator sa denominator.

$$\frac{\left(y^{2}-y-12\right)\left(81y^{3}-25y\right)}{\left(9y^{3}-5y^{2}\right)\left(4y-16\right)}$$

I-factor ang mga expression na hindi pa na-factor.

$$\frac{y\left(y-4\right)\left(9y-5\right)\left(y+3\right)\left(9y+5\right)}{4\left(y-4\right)\left(9y-5\right)y^{2}}$$

I-cancel out ang y\left(y-4\right)\left(9y-5\right) sa parehong numerator at denominator.

$$\frac{\left(y+3\right)\left(9y+5\right)}{4y}$$

Palawakin ang expression.

$$\frac{9y^{2}+32y+15}{4y}$$

Palawakin

$$\frac{9y}{4}+8+\frac{15}{4y}$$

Maiikling Hakbang sa Solution

I-multiply ang \frac{y^{2}-y-12}{9y^{3}-5y^{2}} sa \frac{81y^{3}-25y}{4y-16} sa pamamagitan ng pag-multiply ng numerator sa numerator at denominator sa denominator.

$$\frac{\left(y^{2}-y-12\right)\left(81y^{3}-25y\right)}{\left(9y^{3}-5y^{2}\right)\left(4y-16\right)}$$

I-factor ang mga expression na hindi pa na-factor.

$$\frac{y\left(y-4\right)\left(9y-5\right)\left(y+3\right)\left(9y+5\right)}{4\left(y-4\right)\left(9y-5\right)y^{2}}$$

I-cancel out ang y\left(y-4\right)\left(9y-5\right) sa parehong numerator at denominator.

$$\frac{\left(y+3\right)\left(9y+5\right)}{4y}$$

Palawakin ang expression.

$$\frac{9y^{2}+32y+15}{4y}$$