Lutasin ang f:y=-3x^2+2x-3

$$f : y = - 3 x ^ { 2 } + 2 x - 3$$

I-solve ang f

$$f=-y\left(3x^{2}-2x+3\right)$$

$$y\neq 0$$

Mga Hakbang sa Pagso-solve ng Linear Equation

Ang equation ay nasa standard form.

$$\frac{1}{y}f=-3x^{2}+2x-3$$

I-divide ang magkabilang dulo ng equation gamit ang y^{-1}.

$$\frac{\frac{1}{y}fy}{1}=\frac{\left(-3x^{2}+2x-3\right)y}{1}$$

Kapag na-divide gamit ang y^{-1}, ma-a-undo ang multiplication gamit ang y^{-1}.

$$f=\frac{\left(-3x^{2}+2x-3\right)y}{1}$$

I-divide ang -3x^{2}+2x-3 gamit ang y^{-1}.

$$f=y\left(-3x^{2}+2x-3\right)$$

I-solve ang x (complex solution)

$$x=\frac{-\sqrt{y\left(-8y-3f\right)}+y}{3y}$$

$$x=\frac{\sqrt{-y\left(8y+3f\right)}+y}{3y}\text{, }y\neq 0$$

I-solve ang x

$$x=\frac{-\sqrt{y\left(-8y-3f\right)}+y}{3y}$$

$$x=\frac{\sqrt{-y\left(8y+3f\right)}+y}{3y}\text{, }\left(y>0\text{ and }f\leq -\frac{8y}{3}\right)\text{ or }\left(f\geq -\frac{8y}{3}\text{ and }y<0\right)\text{ or }\left(y\neq 0\text{ and }f=-\frac{8y}{3}\right)$$