Lutasin ang 32*10^3(-2)+543*10^4(-3)=

$$32 \times { 10 }^{ 3(-2) } +543 \times { 10 }^{ 4(-3) } =$$

I-evaluate

$$\frac{32000543}{1000000000000}\approx 0.000032001$$

Mga Hakbang ng Solution

I-multiply ang 3 at -2 para makuha ang -6.

$$32\times 10^{-6}+543\times 10^{4\left(-3\right)}$$

Kalkulahin ang 10 sa power ng -6 at kunin ang \frac{1}{1000000}.

$$32\times \frac{1}{1000000}+543\times 10^{4\left(-3\right)}$$

I-multiply ang 32 at \frac{1}{1000000} para makuha ang \frac{1}{31250}.

$$\frac{1}{31250}+543\times 10^{4\left(-3\right)}$$

I-multiply ang 4 at -3 para makuha ang -12.

$$\frac{1}{31250}+543\times 10^{-12}$$

Kalkulahin ang 10 sa power ng -12 at kunin ang \frac{1}{1000000000000}.

$$\frac{1}{31250}+543\times \frac{1}{1000000000000}$$

I-multiply ang 543 at \frac{1}{1000000000000} para makuha ang \frac{543}{1000000000000}.

$$\frac{1}{31250}+\frac{543}{1000000000000}$$

Idagdag ang \frac{1}{31250} at \frac{543}{1000000000000} para makuha ang \frac{32000543}{1000000000000}.

$$\frac{32000543}{1000000000000}$$

I-factor

$$\frac{29 \cdot 1103467}{2 ^ {12} \cdot 5 ^ {12}} = 3.2000542999999992 \times 10^{-5}$$