Lutasin ang 3w^4+6w^2+3

$$3 w ^ { 4 } + 6 w ^ { 2 } + 3$$

I-factor

$$3\left(w^{2}+1\right)^{2}$$

Mga Hakbang ng Solution

I-factor out ang 3.

$$3\left(w^{4}+2w^{2}+1\right)$$

Isaalang-alang ang w^{4}+2w^{2}+1. Gamitin ang perfect square formula na a^{2}+2ab+b^{2}=\left(a+b\right)^{2}, kung saan a=w^{2} at b=1.

$$\left(w^{2}+1\right)^{2}$$

I-rewrite ang kumpletong naka-factor na expression. Ang polynomial w^{2}+1 ay hindi naka-factor dahil wala itong anumang rational root.

$$3\left(w^{2}+1\right)^{2}$$

I-evaluate

$$3\left(w^{2}+1\right)^{2}$$