Lutasin ang 3b^4+18b^3+27b^2

$$3 b ^ { 4 } + 18 b ^ { 3 } + 27 b ^ { 2 }$$

I-factor

$$3b^{2}\left(b+3\right)^{2}$$

Mga Hakbang ng Solution

I-factor out ang 3.

$$3\left(b^{4}+6b^{3}+9b^{2}\right)$$

Isaalang-alang ang b^{4}+6b^{3}+9b^{2}. I-factor out ang b^{2}.

$$b^{2}\left(b^{2}+6b+9\right)$$

Isaalang-alang ang b^{2}+6b+9. Gamitin ang perfect square formula na p^{2}+2pq+q^{2}=\left(p+q\right)^{2}, kung saan p=b at q=3.

$$\left(b+3\right)^{2}$$

I-rewrite ang kumpletong naka-factor na expression.

$$3b^{2}\left(b+3\right)^{2}$$

I-evaluate

$$3\left(b\left(b+3\right)\right)^{2}$$