Lutasin ang 3a^2-7b^2-9a^3+21ab^2

$$3 a ^ { 2 } - 7 b ^ { 2 } - 9 a ^ { 3 } + 21 a b ^ { 2 }$$

I-factor

$$\left(1-3a\right)\left(3a^{2}-7b^{2}\right)$$

Mga Hakbang ng Solution

Gawin ang grouping na 3a^{2}-7b^{2}-9a^{3}+21ab^{2}=\left(3a^{2}-7b^{2}\right)+\left(-9a^{3}+21ab^{2}\right), at i-factor out ang -3a sa -9a^{3}+21ab^{2}.

$$3a^{2}-7b^{2}-3a\left(3a^{2}-7b^{2}\right)$$

I-factor out ang common term na 3a^{2}-7b^{2} gamit ang distributive property.

$$\left(3a^{2}-7b^{2}\right)\left(1-3a\right)$$

I-evaluate

$$\left(1-3a\right)\left(3a^{2}-7b^{2}\right)$$