Lutasin ang 1.02^12+(2*1.02^9)+(2*1.0)

$$1.02 ^ { 12 } + ( 2 \cdot 1.02 ^ { 9 } ) + ( 2 \cdot 1.0 )$$

I-evaluate

$$5.658426931807167142301696$$

Mga Hakbang ng Solution

Kalkulahin ang 1.02 sa power ng 12 at kunin ang 1.268241794562545318301696.

$$1.268241794562545318301696+2\times 1.02^{9}+2\times 1$$

Kalkulahin ang 1.02 sa power ng 9 at kunin ang 1.195092568622310912.

$$1.268241794562545318301696+2\times 1.195092568622310912+2\times 1$$

I-multiply ang 2 at 1.195092568622310912 para makuha ang 2.390185137244621824.

$$1.268241794562545318301696+2.390185137244621824+2\times 1$$

Idagdag ang 1.268241794562545318301696 at 2.390185137244621824 para makuha ang 3.658426931807167142301696.

$$3.658426931807167142301696+2\times 1$$

I-multiply ang 2 at 1 para makuha ang 2.

$$3.658426931807167142301696+2$$

Idagdag ang 3.658426931807167142301696 at 2 para makuha ang 5.658426931807167142301696.

$$5.658426931807167142301696$$

I-factor

$$\frac{71089 \cdot 19432709528172209}{2 ^ {12} \cdot 5 ^ {24}} = 5\frac{1.6074876264823403 \times 10^{20}}{2.44140625 \times 10^{20}} = 5.658426931807167$$