Lutasin ang -2/3+5/3b^3-(-1/6)+1-(-1/7b^3)+frac{1}{2}-(frac{2}{7}b^3-frac{2}{3}b^3)

$$- \frac { 2 } { 3 } + \frac { 5 } { 3 } b ^ { 3 } - ( - \frac { 1 } { 6 } ) + 1 - ( - \frac { 1 } { 7 } b ^ { 3 } ) + \frac { 1 } { 2 } - ( \frac { 2 } { 7 } b ^ { 3 } - \frac { 2 } { 3 } b ^ { 3 } )$$

I-evaluate

$$\frac{46b^{3}}{21}+1$$

Mga Hakbang ng Solution

Ang kabaliktaran ng -\frac{1}{6} ay \frac{1}{6}.

$$-\frac{2}{3}+\frac{5}{3}b^{3}+\frac{1}{6}+1-\left(-\frac{1}{7}b^{3}\right)+\frac{1}{2}-\left(\frac{2}{7}b^{3}-\frac{2}{3}b^{3}\right)$$

Idagdag ang -\frac{2}{3} at \frac{1}{6} para makuha ang -\frac{1}{2}.

$$-\frac{1}{2}+\frac{5}{3}b^{3}+1-\left(-\frac{1}{7}b^{3}\right)+\frac{1}{2}-\left(\frac{2}{7}b^{3}-\frac{2}{3}b^{3}\right)$$

Idagdag ang -\frac{1}{2} at 1 para makuha ang \frac{1}{2}.

$$\frac{1}{2}+\frac{5}{3}b^{3}-\left(-\frac{1}{7}b^{3}\right)+\frac{1}{2}-\left(\frac{2}{7}b^{3}-\frac{2}{3}b^{3}\right)$$

Ang kabaliktaran ng -\frac{1}{7}b^{3} ay \frac{1}{7}b^{3}.

$$\frac{1}{2}+\frac{5}{3}b^{3}+\frac{1}{7}b^{3}+\frac{1}{2}-\left(\frac{2}{7}b^{3}-\frac{2}{3}b^{3}\right)$$

Pagsamahin ang \frac{5}{3}b^{3} at \frac{1}{7}b^{3} para makuha ang \frac{38}{21}b^{3}.

$$\frac{1}{2}+\frac{38}{21}b^{3}+\frac{1}{2}-\left(\frac{2}{7}b^{3}-\frac{2}{3}b^{3}\right)$$

Idagdag ang \frac{1}{2} at \frac{1}{2} para makuha ang 1.

$$1+\frac{38}{21}b^{3}-\left(\frac{2}{7}b^{3}-\frac{2}{3}b^{3}\right)$$

Pagsamahin ang \frac{2}{7}b^{3} at -\frac{2}{3}b^{3} para makuha ang -\frac{8}{21}b^{3}.

$$1+\frac{38}{21}b^{3}-\left(-\frac{8}{21}b^{3}\right)$$

Ang kabaliktaran ng -\frac{8}{21}b^{3} ay \frac{8}{21}b^{3}.

$$1+\frac{38}{21}b^{3}+\frac{8}{21}b^{3}$$

Pagsamahin ang \frac{38}{21}b^{3} at \frac{8}{21}b^{3} para makuha ang \frac{46}{21}b^{3}.

$$1+\frac{46}{21}b^{3}$$

Palawakin

$$\frac{46b^{3}}{21}+1$$

Mga Hakbang ng Solution

Ang kabaliktaran ng -\frac{1}{6} ay \frac{1}{6}.

$$-\frac{2}{3}+\frac{5}{3}b^{3}+\frac{1}{6}+1-\left(-\frac{1}{7}b^{3}\right)+\frac{1}{2}-\left(\frac{2}{7}b^{3}-\frac{2}{3}b^{3}\right)$$

Idagdag ang -\frac{2}{3} at \frac{1}{6} para makuha ang -\frac{1}{2}.

$$-\frac{1}{2}+\frac{5}{3}b^{3}+1-\left(-\frac{1}{7}b^{3}\right)+\frac{1}{2}-\left(\frac{2}{7}b^{3}-\frac{2}{3}b^{3}\right)$$

Idagdag ang -\frac{1}{2} at 1 para makuha ang \frac{1}{2}.

$$\frac{1}{2}+\frac{5}{3}b^{3}-\left(-\frac{1}{7}b^{3}\right)+\frac{1}{2}-\left(\frac{2}{7}b^{3}-\frac{2}{3}b^{3}\right)$$

Ang kabaliktaran ng -\frac{1}{7}b^{3} ay \frac{1}{7}b^{3}.

$$\frac{1}{2}+\frac{5}{3}b^{3}+\frac{1}{7}b^{3}+\frac{1}{2}-\left(\frac{2}{7}b^{3}-\frac{2}{3}b^{3}\right)$$

Pagsamahin ang \frac{5}{3}b^{3} at \frac{1}{7}b^{3} para makuha ang \frac{38}{21}b^{3}.

$$\frac{1}{2}+\frac{38}{21}b^{3}+\frac{1}{2}-\left(\frac{2}{7}b^{3}-\frac{2}{3}b^{3}\right)$$

Idagdag ang \frac{1}{2} at \frac{1}{2} para makuha ang 1.

$$1+\frac{38}{21}b^{3}-\left(\frac{2}{7}b^{3}-\frac{2}{3}b^{3}\right)$$

Pagsamahin ang \frac{2}{7}b^{3} at -\frac{2}{3}b^{3} para makuha ang -\frac{8}{21}b^{3}.

$$1+\frac{38}{21}b^{3}-\left(-\frac{8}{21}b^{3}\right)$$

Ang kabaliktaran ng -\frac{8}{21}b^{3} ay \frac{8}{21}b^{3}.

$$1+\frac{38}{21}b^{3}+\frac{8}{21}b^{3}$$

Pagsamahin ang \frac{38}{21}b^{3} at \frac{8}{21}b^{3} para makuha ang \frac{46}{21}b^{3}.

$$1+\frac{46}{21}b^{3}$$