Lutasin ang (log4+2)^2-(log4+4)*log4=

$$( \log 4 + 2 ) ^ { 2 } - ( \log 4 + 4 ) \cdot \log 4 =$$

I-evaluate

$$4$$

Mga Hakbang ng Solution

Gamitin ang binomial theorem na \left(a+b\right)^{2}=a^{2}+2ab+b^{2} para palawakin ang \left(\log_{10}\left(4\right)+2\right)^{2}.

$$\left(\log_{10}\left(4\right)\right)^{2}+4\log_{10}\left(4\right)+4-\left(\log_{10}\left(4\right)+4\right)\log_{10}\left(4\right)$$

Gamitin ang distributive property para i-multiply ang \log_{10}\left(4\right)+4 gamit ang \log_{10}\left(4\right).

$$\left(\log_{10}\left(4\right)\right)^{2}+4\log_{10}\left(4\right)+4-\left(\left(\log_{10}\left(4\right)\right)^{2}+4\log_{10}\left(4\right)\right)$$

Para hanapin ang kabaligtaran ng \left(\log_{10}\left(4\right)\right)^{2}+4\log_{10}\left(4\right), hanapin ang kabaligtaran ng bawat term.

$$\left(\log_{10}\left(4\right)\right)^{2}+4\log_{10}\left(4\right)+4-\left(\log_{10}\left(4\right)\right)^{2}-4\log_{10}\left(4\right)$$

Pagsamahin ang \left(\log_{10}\left(4\right)\right)^{2} at -\left(\log_{10}\left(4\right)\right)^{2} para makuha ang 0.

$$4\log_{10}\left(4\right)+4-4\log_{10}\left(4\right)$$

Pagsamahin ang 4\log_{10}\left(4\right) at -4\log_{10}\left(4\right) para makuha ang 0.

$$4$$

I-factor

$$2^{2}$$