Lutasin ang z^2-25*10^-12+16*10^-12

$${ z }^{ 2 } -25 \times { 10 }^{ -12 } +16 \times { 10 }^{ -12 }$$

I-evaluate

$$z^{2}-\frac{9}{1000000000000}$$

Mga Hakbang ng Solution

Kalkulahin ang 10 sa power ng -12 at kunin ang \frac{1}{1000000000000}.

$$z^{2}-25\times \frac{1}{1000000000000}+16\times 10^{-12}$$

I-multiply ang 25 at \frac{1}{1000000000000} para makuha ang \frac{1}{40000000000}.

$$z^{2}-\frac{1}{40000000000}+16\times 10^{-12}$$

Kalkulahin ang 10 sa power ng -12 at kunin ang \frac{1}{1000000000000}.

$$z^{2}-\frac{1}{40000000000}+16\times \frac{1}{1000000000000}$$

I-multiply ang 16 at \frac{1}{1000000000000} para makuha ang \frac{1}{62500000000}.

$$z^{2}-\frac{1}{40000000000}+\frac{1}{62500000000}$$

Idagdag ang -\frac{1}{40000000000} at \frac{1}{62500000000} para makuha ang -\frac{9}{1000000000000}.

$$z^{2}-\frac{9}{1000000000000}$$

I-factor

$$\frac{\left(1000000z-3\right)\left(1000000z+3\right)}{1000000000000}$$