Lutasin ang y^2-8x-6y+25=0 | Microsoft Math Solver

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5 mga problemang katulad ng:

Katulad na mga Problema mula sa Web Search

https://socratic.org/questions/how-do-you-identity-if-the-equation-x-2-y-2-8x-6y-5-0-is-a-parabola-circle-ellip

https://socratic.org/questions/how-do-you-find-the-center-and-radius-of-the-circle-given-by-the-equation-x-2-y-

https://math.stackexchange.com/questions/798273/find-the-equations-of-the-circles-that-have-centre-0-0-and-touch-the-circle

https://socratic.org/questions/how-do-you-find-the-center-and-radius-of-the-circle-given-x-2-y-2-3x-8y-20

https://socratic.org/questions/how-do-you-find-the-standard-form-of-2y-2-x-8y-5-0-and-what-kind-of-a-conic-is-i

https://socratic.org/questions/how-do-you-write-the-equation-of-the-circle-in-standard-form-identify-the-center-1

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-8x-6y+25=-y^{2}

I-subtract ang y^{2} mula sa magkabilang dulo. Magiging negative ang anumang isu-subtract sa zero.

-8x+25=-y^{2}+6y

Idagdag ang 6y sa parehong bahagi.

-8x=-y^{2}+6y-25

I-subtract ang 25 mula sa magkabilang dulo.

\frac{-8x}{-8}=\frac{-y^{2}+6y-25}{-8}

I-divide ang magkabilang dulo ng equation gamit ang -8.

x=\frac{-y^{2}+6y-25}{-8}

Kapag na-divide gamit ang -8, ma-a-undo ang multiplication gamit ang -8.

x=\frac{y^{2}}{8}-\frac{3y}{4}+\frac{25}{8}

I-divide ang -y^{2}+6y-25 gamit ang -8.

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