Lutasin ang sqrt{x}=sqrt{y}+sqrt{z}

$$\sqrt{ x } = \sqrt{ y } + \sqrt{ z }$$

I-solve ang x

$$x=\left(\sqrt{y}+\sqrt{z}\right)^{2}$$

$$y\geq 0\text{ and }z\geq 0$$

Mga Hakbang sa Pagso-solve ng Mga Radical Equation

I-square ang magkabilang dulo ng equation.

$$x=\left(\sqrt{y}+\sqrt{z}\right)^{2}$$

I-solve ang x (complex solution)

$$x=\left(\sqrt{y}+\sqrt{z}\right)^{2}$$

$$\left(y=0\text{ and }z=0\right)\text{ or }arg(\sqrt{y}+\sqrt{z})<\pi$$

I-solve ang y (complex solution)

$$y=\left(\sqrt{x}-\sqrt{z}\right)^{2}$$

$$x=z\text{ or }arg(\sqrt{x}-\sqrt{z})<\pi$$

I-solve ang y

$$y=\left(\sqrt{x}-\sqrt{z}\right)^{2}$$

$$x\geq 0\text{ and }z\geq 0\text{ and }\sqrt{x}-\sqrt{z}\geq 0$$