Lutasin ang phi=(4500N*C^{-1})(123.36*10^{-4}m^2)cos{tan^-1(18.5*10^-2m)/(frac{122{2}*10^-2m)}}

$$\phi = ( 4500 N \cdot C ^ { - 1 } ) ( 123.36 \times 10 ^ { - 4 } m ^ { 2 } ) \cos \{ \tan ^ { - 1 } \frac { ( 18.5 \times 10 ^ { - 2 } m ) } { ( \frac { 122 } { 2 } \times 10 ^ { - 2 } m ) } \}$$

I-solve ang N

$$N=\frac{125\sqrt{16253}Cϕ}{846558m^{2}}$$

$$C\neq 0\text{ and }m\neq 0$$

Mga Hakbang sa Pagso-solve ng Linear Equation

I-multiply ang 4500 at 123.36 para makuha ang 555120.

$$ϕ=555120NC^{-1}\times 10^{-4}m^{2}\cos(\arctan(\frac{18.5\times 10^{-2}m}{\frac{122}{2}\times 10^{-2}m}))$$

Kalkulahin ang 10 sa power ng -4 at kunin ang \frac{1}{10000}.

$$ϕ=555120NC^{-1}\times \frac{1}{10000}m^{2}\cos(\arctan(\frac{18.5\times 10^{-2}m}{\frac{122}{2}\times 10^{-2}m}))$$

I-multiply ang 555120 at \frac{1}{10000} para makuha ang \frac{6939}{125}.

$$ϕ=\frac{6939}{125}NC^{-1}m^{2}\cos(\arctan(\frac{18.5\times 10^{-2}m}{\frac{122}{2}\times 10^{-2}m}))$$

Kalkulahin ang 10 sa power ng -2 at kunin ang \frac{1}{100}.

$$ϕ=\frac{6939}{125}NC^{-1}m^{2}\cos(\arctan(\frac{18.5\times \frac{1}{100}m}{\frac{122}{2}\times 10^{-2}m}))$$

I-multiply ang 18.5 at \frac{1}{100} para makuha ang \frac{37}{200}.

$$ϕ=\frac{6939}{125}NC^{-1}m^{2}\cos(\arctan(\frac{\frac{37}{200}m}{\frac{122}{2}\times 10^{-2}m}))$$

I-divide ang 122 gamit ang 2 para makuha ang 61.

$$ϕ=\frac{6939}{125}NC^{-1}m^{2}\cos(\arctan(\frac{\frac{37}{200}m}{61\times 10^{-2}m}))$$

Kalkulahin ang 10 sa power ng -2 at kunin ang \frac{1}{100}.

$$ϕ=\frac{6939}{125}NC^{-1}m^{2}\cos(\arctan(\frac{\frac{37}{200}m}{61\times \frac{1}{100}m}))$$

I-multiply ang 61 at \frac{1}{100} para makuha ang \frac{61}{100}.

$$ϕ=\frac{6939}{125}NC^{-1}m^{2}\cos(\arctan(\frac{\frac{37}{200}m}{\frac{61}{100}m}))$$

I-cancel out ang m sa parehong numerator at denominator.

$$ϕ=\frac{6939}{125}NC^{-1}m^{2}\cos(\arctan(\frac{\frac{37}{200}}{\frac{61}{100}}))$$

I-divide ang \frac{37}{200} gamit ang \frac{61}{100} sa pamamagitan ng pagmu-multiply sa \frac{37}{200} gamit ang reciprocal ng \frac{61}{100}.

$$ϕ=\frac{6939}{125}NC^{-1}m^{2}\cos(\arctan(\frac{37}{200}\times \frac{100}{61}))$$

I-multiply ang \frac{37}{200} at \frac{100}{61} para makuha ang \frac{37}{122}.

$$ϕ=\frac{6939}{125}NC^{-1}m^{2}\cos(\arctan(\frac{37}{122}))$$

Pagpalitin ang magkabilang panig para nasa kaliwang bahagi ang lahat ng variable na term.

$$\frac{6939}{125}NC^{-1}m^{2}\cos(\arctan(\frac{37}{122}))=ϕ$$

Ang equation ay nasa standard form.

$$\frac{6939\cos(\arctan(\frac{37}{122}))m^{2}}{125C}N=ϕ$$

I-divide ang magkabilang dulo ng equation gamit ang \frac{6939}{125}C^{-1}m^{2}\cos(\arctan(\frac{37}{122})).

$$\frac{\frac{6939\cos(\arctan(\frac{37}{122}))m^{2}}{125C}N\times 125C}{6939\cos(\arctan(\frac{37}{122}))m^{2}}=\frac{ϕ\times 125C}{6939\cos(\arctan(\frac{37}{122}))m^{2}}$$

Kapag na-divide gamit ang \frac{6939}{125}C^{-1}m^{2}\cos(\arctan(\frac{37}{122})), ma-a-undo ang multiplication gamit ang \frac{6939}{125}C^{-1}m^{2}\cos(\arctan(\frac{37}{122})).

$$N=\frac{ϕ\times 125C}{6939\cos(\arctan(\frac{37}{122}))m^{2}}$$

I-divide ang ϕ gamit ang \frac{6939}{125}C^{-1}m^{2}\cos(\arctan(\frac{37}{122})).

$$N=\frac{125\sqrt{16253}Cϕ}{846558m^{2}}$$

I-solve ang C

$$\left\{\begin{matrix}\\C\neq 0\text{, }&\text{unconditionally}\\C=\frac{846558\sqrt{16253}Nm^{2}}{2031625ϕ}\text{, }&m\neq 0\text{ and }N\neq 0\text{ and }ϕ\neq 0\end{matrix}\right.$$