I-solve ang A
A=\pi n_{3}+\frac{\pi -2B}{2}
n_{3}\in \mathrm{Z}
\exists n_{1}\in \mathrm{Z}\text{ : }\left(B>-\pi n_{1}+\pi n_{3}-\pi \text{ and }B<\pi n_{3}-\pi n_{1}\right)
\exists n_{2}\in \mathrm{Z}\text{ : }\left(B>\pi n_{2}\text{ and }B<\pi n_{2}+\frac{\pi }{2}\right)
I-solve ang B
B=\pi n_{3}+\frac{\pi -2A}{2}
n_{3}\in \mathrm{Z}
\exists n_{1}\in \mathrm{Z}\text{ : }\left(A>-\pi n_{1}+\pi n_{3}-\pi \text{ and }A<\pi n_{3}-\pi n_{1}\right)
\exists n_{2}\in \mathrm{Z}\text{ : }\left(A>\pi n_{2}\text{ and }A<\pi n_{2}+\frac{\pi }{2}\right)
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