Lutasin ang lim(x^4-(x-5)^5/(2-x)^4-2x^4)

\lim ( \frac { x ^ { 4 } - ( x - 5 ) ^ { 5 } } { ( 2 - x ) ^ { 4 } - 2 x ^ { 4 } } )

I-evaluate

\left(Re(\frac{1}{\left(2-x\right)^{4}-2x^{4}})\left(-Im(\left(x-5\right)^{5})+Im(x^{4})\right)+Im(\frac{1}{\left(2-x\right)^{4}-2x^{4}})\left(-Re(\left(x-5\right)^{5})+Re(x^{4})\right)\right)l

Quiz

Complex Number

\lim ( \frac { x ^ { 4 } - ( x - 5 ) ^ { 5 } } { ( 2 - x ) ^ { 4 } - 2 x ^ { 4 } } )

Katulad na mga Problema mula sa Web Search

How do you evaluate the limit of \displaystyle\lim\frac{{{2}{x}^{{2}}-{3}{x}}}{{{x}^{{3}}-{2}{x}^{{2}}+{x}+{6}}} as \displaystyle{x}\to{3} ?

https://socratic.org/questions/how-do-you-evaluate-the-limit-of-lim-2x-2-3x-x-3-2x-2-x-6-as-x-3

\displaystyle\frac{{1}}{{2}}{E}{x}{p}{l}{a}{n}{a}{t}{i}{o}{n}: "the limit in this case can be evaluated by direct substitution" lim_(xto3)(2x^2-3x)/(x^3-2x^2+x+6) ...

What is the value of \displaystyle\lim_{{{x}\rightarrow-{3}}}{\frac{{{x}^{{{2}}}-{9}}}{{{x}^{{{2}}}-{2}{x}-{15}}}} ?

https://socratic.org/questions/what-is-the-value-of-lim-x-rightarrow-3-frac-x-2-9-x-2-2x-15

\displaystyle\frac{{3}}{{4}} Explanation: \displaystyle\lim_{{{x}\to-{3}}}\frac{{{x}^{{2}}-{9}}}{{{x}^{{2}}-{2}{x}-{15}}} By factoring out the numerator and the denominator, \displaystyle=\lim_{{{x}\to-{3}}}\frac{{\cancel{{{\left({x}+{3}\right)}}}{\left({x}-{3}\right)}}}{{\cancel{{{\left({x}+{3}\right)}}}{\left({x}-{5}\right)}}}=\frac{{-{3}-{3}}}{{-{3}-{5}}}=\frac{{-{6}}}{{-{8}}}=\frac{{3}}{{4}} ...

How do you find the limit \displaystyle\lim\frac{{{2}{x}^{{2}}-{3}{x}+{2}}}{{{x}^{{3}}+{5}{x}^{{2}}-{1}}} as \displaystyle{x}\to\infty ?

https://socratic.org/questions/how-do-you-find-the-limit-lim-2x-2-3x-2-x-3-5x-2-1-as-x-oo

\displaystyle\lim_{{{x}\rightarrow\infty}}\frac{{{2}{x}^{{2}}-{3}{x}+{2}}}{{{x}^{{3}}+{5}{x}^{{2}}-{1}}}={0} Explanation: Note that as \displaystyle{x}\rightarrow\infty then \displaystyle\frac{{1}}{{x}},\frac{{1}}{{x}^{{2}}},\frac{{1}}{{x}^{{3}}}\rightarrow{0} ...

How do you evaluate the limit of \displaystyle\lim\frac{{{x}^{{3}}-{x}^{{2}}+{2}{x}}}{{{x}^{{3}}+{4}{x}^{{2}}-{2}{x}}} as \displaystyle{x}\to{0} ?

https://socratic.org/questions/how-do-you-evaluate-the-limit-of-lim-x-3-x-2-2x-x-3-4x-2-2x-as-x-0

\displaystyle\lim_{{{x}\to{0}}}\frac{{{x}^{{3}}-{x}^{{2}}+{2}{x}}}{{{x}^{{3}}+{4}{x}^{{2}}-{2}{x}}}=\frac{{{0}+{0}+{2}}}{{{0}+{0}-{2}}}=-{1} Explanation: \displaystyle\frac{{{x}^{{3}}-{x}^{{2}}+{2}{x}}}{{{x}^{{3}}+{4}{x}^{{2}}-{2}{x}}}=\frac{{{\left({x}^{{2}}-{x}+{2}\right)}{\left(\cancel{{{\left({x}\right)}}}\right)}}}{{{\left({x}^{{2}}+{4}{x}-{2}\right)}{\left(\cancel{{{\left({x}\right)}}}\right)}}}=\frac{{{x}^{{2}}-{x}+{2}}}{{{x}^{{2}}+{4}{x}-{2}}} ...

How do you find \displaystyle\lim_{{{x}\to{2}}}\frac{{{x}^{{3}}-{6}{x}-{2}}}{{{x}^{{3}}-{4}{x}}} using l'Hospital's Rule or otherwise?

https://socratic.org/questions/how-do-you-find-lim-x-3-6x-2-x-3-4x-as-x-2-using-l-hospital-s-rule-or-otherwise

Truong-Son N. Jun 26, 2017 The two-sided limit doesn't exist... graph{(x^3 - 6x - 2)/(x^3 - 4x) [-4.245, 9.8, -1.71, 5.313]} Well, you can approach it with some manipulation. \displaystyle=\lim_{{{x}\to{2}}}\frac{{{x}^{{3}}-{4}{x}-{2}{x}-{2}}}{{{x}^{{3}}-{4}{x}}} ...

How do you find \displaystyle\lim\frac{{{2}{x}^{{2}}-{4}{x}+{1}}}{{{3}{x}^{{2}}+{5}{x}-{6}}} as \displaystyle{x}\to\infty ?

https://socratic.org/questions/how-do-you-find-lim-2x-2-4x-1-3x-2-5x-6-as-x-oo

\displaystyle\lim_{{{x}\to\infty}}\frac{{{2}{x}^{{2}}-{4}{x}+{1}}}{{{3}{x}^{{2}}+{5}{x}-{6}}}=\frac{{2}}{{3}} Explanation: We can manipulate the limit as follows \displaystyle\lim_{{{x}\to\infty}}\frac{{{2}{x}^{{2}}-{4}{x}+{1}}}{{{3}{x}^{{2}}+{5}{x}-{6}}}=\lim_{{{x}\to\infty}}\frac{{{2}{x}^{{2}}-{4}{x}+{1}}}{{{3}{x}^{{2}}+{5}{x}-{6}}}\cdot\frac{{\frac{{1}}{{x}^{{2}}}}}{{\frac{{1}}{{x}^{{2}}}}} ...

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Ekwasyong kwadratiko

{ x } ^ { 2 } - 4 x - 5 = 0

Trigonometry

4 \sin \theta \cos \theta = 2 \sin \theta

\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]

Sabay sabay na equation

\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.

Pagkakaiba iba

\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }

Pagsasama sama

\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x

Mga Limitasyon

\lim _{x \rightarrow-3} \frac{x^{2}-9}{x^{2}+2 x-3}

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