I-solve ang x, y, z
\left\{\begin{matrix}x=\frac{c}{4y_{0}}\text{, }y=-\frac{2\left(491y_{0}+2d\right)}{18y_{0}-5d}\text{, }z=c\text{, }&y_{0}\neq \frac{5c}{18}\text{ and }y_{0}\neq 0\text{ and }d=c\text{ and }b=c\text{ and }a=c\\x=-\frac{9y+491}{2\left(4-5y\right)}\text{, }y\neq \frac{4}{5}\text{, }z=0\text{, }&a=0\text{ and }y_{0}=0\text{ and }b=0\text{ and }c=0\text{ and }d=0\end{matrix}\right.
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