Lutasin ang 1200(1.0025)(1.0025^12-1)/0.0025

$$\frac{ 1200(1.0025)( { 1.0025 }^{ 12 } -1) }{ 0.0025 }$$

I-evaluate

$$14636.15846677972242831246732367522716522216796875$$

Mga Hakbang ng Solution

I-multiply ang 1200 at 1.0025 para makuha ang 1203.

$$\frac{1203\left(1.0025^{12}-1\right)}{0.0025}$$

Kalkulahin ang 1.0025 sa power ng 12 at kunin ang 1.030415956913507320092087421703398227691650390625.

$$\frac{1203\left(1.030415956913507320092087421703398227691650390625-1\right)}{0.0025}$$

I-subtract ang 1 mula sa 1.030415956913507320092087421703398227691650390625 para makuha ang 0.030415956913507320092087421703398227691650390625.

$$\frac{1203\times 0.030415956913507320092087421703398227691650390625}{0.0025}$$

I-multiply ang 1203 at 0.030415956913507320092087421703398227691650390625 para makuha ang 36.590396166949306070781168309188067913055419921875.

$$\frac{36.590396166949306070781168309188067913055419921875}{0.0025}$$

I-expand ang \frac{36.590396166949306070781168309188067913055419921875}{0.0025} sa pamamagitan ng pag-multiply sa parehong numerator at denominator ng 1000000000000000000000000000000000000000000000000.

$$\frac{36590396166949306070781168309188067913055419921875}{2500000000000000000000000000000000000000000000}$$

Bawasan ang fraction \frac{36590396166949306070781168309188067913055419921875}{2500000000000000000000000000000000000000000000} sa pinakamabababang term sa pamamagitan ng pag-extract at pag-cancel out sa 59604644775390625.

$$\frac{613884980018480568999606949455603}{41943040000000000000000000000}$$

I-factor

$$\frac{7 \cdot 13 \cdot 73 \cdot 89 \cdot 127 \cdot 401 \cdot 421 \cdot 24677 \cdot 68743 \cdot 352449337 \cdot 3 ^ {4}}{2 ^ {44} \cdot 5 ^ {22}} = 14636\frac{6.6465784805658235 \times 10^{27}}{4.194304 \times 10^{28}} = 14636.158466779721$$