Ratkaise ∫ (from pi / 4 to pi / 2) of cosx/cosx wrt x | Microsoftin matematiikan ratkaisija

Laske

\frac{\pi }{4}\approx 0,785398163

Ratkaisun vaiheet

\int _ { \pi / 4 } ^ { \pi / 2 } \frac { \cos x } { \cos x } d x

Jaa \cos(x) luvulla \cos(x), jolloin ratkaisuksi tulee 1.

\int _{\frac{\pi }{4}}^{\frac{\pi }{2}}1\mathrm{d}x

Laske ensin määräämätön integraali.

\int 1\mathrm{d}x

Etsi kohteen 1 integraali yleisten integraalisääntöjen taulukon \int a\mathrm{d}x=ax avulla.

Määrätty integraali on integroinnin ylärajaan arvotetun lausekkeen integraali miinus integroinnin alarajaan arvotettu integraali.

\frac{\pi }{2}-\frac{\pi }{4}

Sievennä.

\frac{\pi }{4}

Tietokilpailu

Integration

5 ongelmia, jotka ovat samankaltaisia kuin:

\int _ { \pi / 4 } ^ { \pi / 2 } \frac { \cos x } { \cos x } d x

Samanlaisia ongelmia verkkohausta

How could I show that \int_{0}^{\frac{\pi}{2}} \frac{\cos (nx)}{\cos x}dx converges to zero as n\rightarrow \infty?

https://math.stackexchange.com/questions/1423757/how-could-i-show-that-int-0-frac-pi2-frac-cos-nx-cos-xdx-conv

This integral does not converge to 0 as n \to \infty. Case n = 2m. In this case, the integrand has simple pole at x = \frac{\pi}{2} \frac{\cos 2mx}{\cos x} \sim \frac{(-1)^m}{\frac{\pi}{2} - x} \quad \text{as } x \to \tfrac{\pi}{2}, ...

Integrating \int_0^{\pi/2} \cos^a(x) \cos(bx) \ dx

https://math.stackexchange.com/questions/456899/integrating-int-0-pi-2-cosax-cosbx-dx

\begin{align} &\int_0^{\frac\pi2}\cos^a(x)\cos(bx)\,\mathrm{d}x\\ &=\mathrm{Re}\left(2^{-a}\int_0^{\frac\pi2}\left(e^{ix}+e^{-ix}\right)^ae^{ibx}\,\mathrm{d}x\right)\tag{1}\\ &=\mathrm{Re}\left(2^{-a}\int_0^{\frac\pi2}\left(1+e^{-2ix}\right)^ae^{i(a+b)x}\,\mathrm{d}x\right)\tag{2}\\ &=\mathrm{Re}\left(2^{-a}\int_0^{\frac\pi2}\left(1+e^{-2ix}\right)^ae^{i(a+b+2)x}\,\frac{i}{2}\mathrm{d}e^{-2ix}\right)\tag{3}\\ &=\mathrm{Re}\left(2^{-a}\int_1^{-1}\left(1+u\right)^au^{-(a+b)/2-1}\,\frac{i}{2}\mathrm{d}u\right)\tag{4}\\ &=\mathrm{Re}\left(2^{-a}\int_0^{-1}\left(1+u\right)^au^{-(a+b)/2-1}\,\frac{i}{2}\mathrm{d}u\right)\tag{5}\\ &=\mathrm{Re}\left(2^{-a}\int_0^1\left(1-u\right)^au^{-(a+b)/2-1}e^{i\pi((a+b)/2+1)}\,\frac1{2i}\mathrm{d}u\right)\tag{6}\\ &=\mathrm{Re}\left(2^{-a-1}e^{i\pi((a+b+1)/2)}\int_0^1\left(1-u\right)^au^{-(a+b)/2-1}\,\mathrm{d}u\right)\tag{7}\\ &=2^{-a-1}\cos(\pi(a+b+1)/2)\int_0^1\left(1-u\right)^au^{-(a+b)/2-1}\,\mathrm{d}u\tag{8}\\ &=2^{-a-1}\sin(-\pi(a+b)/2)\frac{\Gamma(a+1)\Gamma(-(a+b)/2)}{\Gamma(1+(a-b)/2)}\tag{9}\\ &=\frac{\pi\,2^{-a-1}\,\Gamma(a+1)}{\Gamma(1+(a-b)/2)\,\Gamma(1+(a+b)/2)}\tag{10} \end{align} ...

What is \int\limits_{-\frac{\pi}{2}}^{\frac{\pi}{2}}\cos^4x dx?

https://www.quora.com/What-is-int-limits_-frac-pi-2-frac-pi-2-cos-4x-dx

I will take a longer detour to find the answer to this question but it is worth the effort. Let’s denote J this integral. First, by symmetry, J=2\int_{0}^{\frac{\pi}{2}}\cos^{4}xdx Now, let ...

How will you integrate \displaystyle\int_{-\pi/2}^{\pi/2}\cos^{8}x \: \mathrm{d}x ?

https://www.quora.com/How-will-you-integrate-displaystyle-int_-pi-2-pi-2-cos-8-x-mathrm-d-x

I would use the fact that \cos(2x)=2\cos^2x-1, aka \cos^2x=\frac{\cos(2x)+1}{2}, multiple times. Use that to rewrite your cos^8, then you’ll have to expand the fourth power of a binomial, ...

Evaluating \int_0^{\pi/4} (\cos 2x)^{3/2} \cos x \, dx

https://math.stackexchange.com/q/2400460

Set \cos 2x = \sin^2\theta. Then \cos x = \sqrt{\frac{1+\sin^2\theta}{2}} \qquad \text{and} \qquad \left|\frac{dx}{d\theta}\right| = \frac{\sin\theta}{\sqrt{1+\sin^2\theta}}. So we have \int_{0}^{\frac{\pi}{4}} \cos^{3/2}(2x) \cos x \, dx = \frac{1}{\sqrt{2}} \int_{0}^{\frac{\pi}{2}} \sin^4\theta \, d\theta = \frac{3\pi}{16\sqrt{2}}. ...

is this trig integral doable using contour integration?.

https://math.stackexchange.com/questions/381346/is-this-trig-integral-doable-using-contour-integration

\newcommand{\+}{^{\dagger}} \newcommand{\angles}[1]{\left\langle\, #1 \,\right\rangle} \newcommand{\braces}[1]{\left\lbrace\, #1 \,\right\rbrace} \newcommand{\bracks}[1]{\left\lbrack\, #1 \,\right\rbrack} \newcommand{\ceil}[1]{\,\left\lceil\, #1 \,\right\rceil\,} \newcommand{\dd}{{\rm d}} \newcommand{\down}{\downarrow} \newcommand{\ds}[1]{\displaystyle{#1}} \newcommand{\expo}[1]{\,{\rm e}^{#1}\,} \newcommand{\fermi}{\,{\rm f}} \newcommand{\floor}[1]{\,\left\lfloor #1 \right\rfloor\,} \newcommand{\half}{{1 \over 2}} \newcommand{\ic}{{\rm i}} \newcommand{\iff}{\Longleftrightarrow} \newcommand{\imp}{\Longrightarrow} \newcommand{\isdiv}{\,\left.\right\vert\,} \newcommand{\ket}[1]{\left\vert #1\right\rangle} \newcommand{\ol}[1]{\overline{#1}} \newcommand{\pars}[1]{\left(\, #1 \,\right)} \newcommand{\partiald}[3][]{\frac{\partial^{#1} #2}{\partial #3^{#1}}} \newcommand{\pp}{{\cal P}} \newcommand{\root}[2][]{\,\sqrt[#1]{\vphantom{\large A}\,#2\,}\,} \newcommand{\sech}{\,{\rm sech}} \newcommand{\sgn}{\,{\rm sgn}} \newcommand{\totald}[3][]{\frac{{\rm d}^{#1} #2}{{\rm d} #3^{#1}}} \newcommand{\ul}[1]{\underline{#1}} \newcommand{\verts}[1]{\left\vert\, #1 \,\right\vert} \newcommand{\wt}[1]{\widetilde{#1}} ...

Jakaa

Kopioitu leikepöydälle

\int _{\frac{\pi }{4}}^{\frac{\pi }{2}}1\mathrm{d}x

Jaa \cos(x) luvulla \cos(x), jolloin ratkaisuksi tulee 1.

\int 1\mathrm{d}x

Laske ensin määräämätön integraali.

Etsi kohteen 1 integraali yleisten integraalisääntöjen taulukon \int a\mathrm{d}x=ax avulla.

\frac{\pi }{2}-\frac{\pi }{4}

Määrätty integraali on integroinnin ylärajaan arvotetun lausekkeen integraali miinus integroinnin alarajaan arvotettu integraali.

\frac{\pi }{4}

Sievennä.

Esimerkkejä

Toisen asteen yhtälö

{ x } ^ { 2 } - 4 x - 5 = 0

Trigonometria

4 \sin \theta \cos \theta = 2 \sin \theta

Ensimmäisen asteen yhtälö

\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]

Samanaikainen kaava

\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.

Erilaistuminen

\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }

Integraatio

\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x

Rajoitukset

\lim _{x \rightarrow-3} \frac{x^{2}-9}{x^{2}+2 x-3}

Aiheet

Aiheet

Samanlaisia ongelmia verkkohausta

Jakaa

Esimerkkejä