حل {l}{sin(2θ)=3/16}{a=arcsin(3/16)}{b=a}{text{Solvefor}ctext{where}}{c=b}

$$\left. \begin{array} { l } { \sin(2 \theta) = \frac{3}{16} }\\ { a = \arcsin(\frac{3}{16}) }\\ { b = a }\\ { \text{Solve for } c \text{ where} } \\ { c = b } \end{array} \right.$$

برای θ،a،b،c حل کنید

$$\theta =\frac{2\pi n_{1}+\arcsin(\frac{3}{16})}{2}\text{, }n_{1}\in \mathrm{Z}\text{, }a=\arcsin(\frac{3}{16})\approx 0.188616386\text{, }b=\arcsin(\frac{3}{16})\approx 0.188616386\text{, }c=\arcsin(\frac{3}{16})\approx 0.188616386$$

$$\theta =\frac{2\pi n_{2}+\pi -\arcsin(\frac{3}{16})}{2}\text{, }n_{2}\in \mathrm{Z}\text{, }a=\arcsin(\frac{3}{16})\approx 0.188616386\text{, }b=\arcsin(\frac{3}{16})\approx 0.188616386\text{, }c=\arcsin(\frac{3}{16})\approx 0.188616386$$