Resolver a_{n}=3*(-2)^n-1

$$a _ { n } = 3 \cdot ( - 2 ) ^ { n - 1 }$$

Ebatzi: a_n (complex solution)

$$a_{n}=-\frac{3\left(-2\right)^{n}}{2}$$

Ebatzi: n (complex solution)

$$n=\frac{\ln(a_{n})-\ln(\frac{3}{2})+\pi i}{\ln(2)+\pi i}+\frac{2\pi n_{1}i}{\ln(2)+\pi i}$$

$$n_{1}\in \mathrm{Z}$$

$$a_{n}\neq 0$$

Ebatzi: a_n

$$a_{n}=-\frac{3\left(-2\right)^{n}}{2}$$

$$Denominator(n)\text{bmod}2=1$$

Ebatzi: n

$$n=\frac{\ln(a_{n})+\ln(\frac{2}{3})}{\ln(2)}$$

$$a_{n}>0\text{ and }Numerator(\frac{-\ln(a_{n})+\ln(3)}{\ln(2)})\text{bmod}2=0\text{ and }Denominator(\frac{-\ln(a_{n})+\ln(3)}{\ln(2)})\text{bmod}2=1$$