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9 t = 54

Ebatzi: t

t = 6

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Azterketa

Linear Equation

9 t = 54

Bilaketaren antzeko arazoak webgunean

9 t = 2 t 2

http://www.tiger-algebra.com/drill/9t=2t2/

9t=2t2 Two solutions were found : t = 9/2 = 4.500 t = 0 Reformatting the input : Changes made to your input should not affect the solution: (1): "t2" was replaced by "t^2". Rearrange: ...

t = 0

, a particle is located at

x = 25 m

and has a velocity of

15 \frac{m}{s}

in the positive

x

direction. The ...

https://socratic.org/questions/at-t-0-a-particle-is-located-at-x-25m-and-has-a-velocity-of-15m-s-in-the-positiv

the position of the particle at t=5 is \frac{2 5}{6} m

using diagram

a (t) = a_{i} - k \cdot t

What is the average speed of an object that is moving at

2 \frac{m}{s}

t = 0

and accelerates at a rate of

a (t) = 5 - t

https://socratic.org/questions/what-is-the-average-speed-of-an-object-that-is-moving-at-2-m-s-at-t-0-and-accele

P dilip_k Apr 20, 2016 Given acceleration

a (t) = 5 - t

\frac{d v}{d t} = 5 - t

\Rightarrow d v = 5 d t - t d t

Probability of duration of a phone calls like a draw made random with replacement

https://math.stackexchange.com/questions/388350/probability-of-duration-of-a-phone-calls-like-a-draw-made-random-with-replacemen

So you have 100 random variables, each with average

μ_{0} = 8.5

minutes and standard deviation

σ_{0} = 3

minutes. The central limit theorem thus tells you that the sum of these random variables is ...

Force to use in harmonic oscillation through the inside of a planet

https://physics.stackexchange.com/questions/36460/force-to-use-in-harmonic-oscillation-through-the-inside-of-a-planet

The key to this problem is the fact that the planet's mass

M

as it appears in Newton's law of gravitation,

F = \frac{G M m}{r ^{2}},

is not actually constant. This is because the layers of the planet ...

Time constants and steady states of decaying quantities

https://math.stackexchange.com/q/665415

The point is that after five time constants, the error from the equilibrium state is multiplied by

exp (- 5) \approx 0.0067

, or divided by about

150

. If you didn't start too far from equilibrium, ...

Partekatu

Kopiatu portapapeletan

t=\frac{54}{9}

Zatitu ekuazioaren bi aldeak 9 balioarekin.

t=6

6 lortzeko, zatitu 54 9 balioarekin.

Adibideak

Ekuazio koadratikoa

x^{2} - 4 x - 5 = 0

4 sin θ cos θ = 2 sin θ

Ekuazio lineala

y = 3 x + 4

699 * 533

[2534] [2 - 1 0135]

Aldibereko ekuazioa

{8 x + 2 y = 46 7 x + 3 y = 47

Diferentziazioa

\frac{d}{d x} \frac{( 3 x ^{2} - 2 )}{( x - 5 )}

\int_{0}^{1} x e^{- x^{2}} d x

x \to - 3 lim \frac{x ^{2} - 9}{x ^{2} + 2 x - 3}