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2567, 7

2567, 7

Faktorizatu

\frac{3 1 7 \cdot 3 ^{4}}{2 \cdot 5} = 2567 \frac{7}{1 0} = 2567.7

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Ebaluatu

2567, 7

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Grafikoa

Azterketa

2567, 7

Bilaketaren antzeko arazoak webgunean

4 digit number be arranged from 7,2,6,8,5,1 and divisible by 5

https://math.stackexchange.com/questions/2925096/4-digit-number-be-arranged-from-7-2-6-8-5-1-and-divisible-by-5

We have four digits to fill. In order for the final number to be divisible by 5, we have to have 5 as the last digit. All other possible numbers as final digit will result in a number not divisible by ...

S_{n}

k

https://math.stackexchange.com/q/2576067

As requested, here is the problem done out in steps. Start with data,

{X_{1}, \dots, X_{n}}

, which is in this case

{1, 2, 3, 5, 6, 7}

n = 6

. Form the (multi)set of differences

{∣ X_{i} - X_{j} ∣; i < j} = {1, 1, 1, 1, 2, 2, 2, 3, 3, 4, 4, 4, 5, 5, 6}

k

-element subsets of

[n]

https://math.stackexchange.com/q/1954299

r

-set is ordered, and the

w

-tuples are unordered--for example, (12)(45)(67) and (12)(54)(76) are the same but (45)(12)(67) is different--multinomial coefficients suffice:

(k n) \cdot (w , w , w , \dots , w k) = \frac{n !}{k ! ( n - k ) !} \cdot \frac{k !}{( w ! ) ^{r}} = \frac{n !}{( n - w r ) ! ( w ! ) ^{r}} .

201 1^{t h}

term of the sequence

2, 3, 5, 6, 7, 8, 10, 11, \dots

https://math.stackexchange.com/questions/2028437/find-the-2011th-term-of-the-sequence-2-3-5-6-7-8-10-11

Hint: One way to continue this sequence is to eliminate all squares:

1 = 1^{2}, 4 = 2^{2}, 9 = 3^{2}, \dots, 4 5^{2} = 2025

Computing (the number) of paths in a directed graph starting from the initial state

https://math.stackexchange.com/questions/1727182/computing-the-number-of-paths-in-a-directed-graph-starting-from-the-initial-st

There might be exponentially many maximal primitive paths – just take

n

copies of graph given by

V = {0, 1, 2, 3}, E = {(0, 1), (0, 2), (1, 3), (2, 3)},

and connect each

3

0

Generator matrix for linear

[8, 5, 3]

https://math.stackexchange.com/questions/2732046/generator-matrix-for-linear-8-5-3-code

From your details, your code is binary (you should mention that). You always have that

G_{2}

generates some code (its row space). To show that it is a generator matrix for that code, you need to ...

Partekatu

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x^{2} - 4 x - 5 = 0

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y = 3 x + 4

699 * 533

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\frac{d}{d x} \frac{( 3 x ^{2} - 2 )}{( x - 5 )}

\int_{0}^{1} x e^{- x^{2}} d x

x \to - 3 lim \frac{x ^{2} - 9}{x ^{2} + 2 x - 3}