Resolver {r}{(1/3)^{8}+8*(2/3)(1/3)^{7}+8!/6!2!(frac{2}{3})^{2}(frac{1}{3})^{6}+frac{8!}{5!3!}(frac{2}{3})^{3}(frac{1}{3})^{5}+frac{8!}{4!4!}(frac{2}{3})^4(frac{1}{3})^4}{quad+frac{8!}{3!5!}(frac{2}{3})^5(frac{1}{3})^3}

$$\left. \begin{array} { r } { ( \frac { 1 } { 3 } ) ^ { 8 } + 8 \cdot ( \frac { 2 } { 3 } ) ( \frac { 1 } { 3 } ) ^ { 7 } + \frac { 8 ! } { 6 ! 2 ! } ( \frac { 2 } { 3 } ) ^ { 2 } ( \frac { 1 } { 3 } ) ^ { 6 } + \frac { 8 ! } { 5 ! 3 ! } ( \frac { 2 } { 3 } ) ^ { 3 } ( \frac { 1 } { 3 } ) ^ { 5 } + \frac { 8 ! } { 4 ! 4 ! } ( \frac { 2 } { 3 } ) ^ { 4 } ( \frac { 1 } { 3 } ) ^ { 4 } } \\ { \quad + \frac { 8 ! } { 3 ! 5 ! } ( \frac { 2 } { 3 } ) ^ { 5 } ( \frac { 1 } { 3 } ) ^ { 3 } } \end{array} \right.$$

Ebaluatu

$$\frac{1163}{2187}\approx 0.531778692$$

Ebazpidea

\left(4!\right)^{2} lortzeko, biderkatu 4! eta 4!.

$$\left(\frac{1}{3}\right)^{8}+8\times \frac{2}{3}\times \left(\frac{1}{3}\right)^{7}+\frac{8!}{6!\times 2!}\times \left(\frac{2}{3}\right)^{2}\times \left(\frac{1}{3}\right)^{6}+\frac{8!}{5!\times 3!}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

\frac{1}{6561} lortzeko, egin \frac{1}{3} ber 8.

$$\frac{1}{6561}+8\times \frac{2}{3}\times \left(\frac{1}{3}\right)^{7}+\frac{8!}{6!\times 2!}\times \left(\frac{2}{3}\right)^{2}\times \left(\frac{1}{3}\right)^{6}+\frac{8!}{5!\times 3!}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Adierazi 8\times \frac{2}{3} frakzio bakar gisa.

$$\frac{1}{6561}+\frac{8\times 2}{3}\times \left(\frac{1}{3}\right)^{7}+\frac{8!}{6!\times 2!}\times \left(\frac{2}{3}\right)^{2}\times \left(\frac{1}{3}\right)^{6}+\frac{8!}{5!\times 3!}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

16 lortzeko, biderkatu 8 eta 2.

$$\frac{1}{6561}+\frac{16}{3}\times \left(\frac{1}{3}\right)^{7}+\frac{8!}{6!\times 2!}\times \left(\frac{2}{3}\right)^{2}\times \left(\frac{1}{3}\right)^{6}+\frac{8!}{5!\times 3!}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

\frac{1}{2187} lortzeko, egin \frac{1}{3} ber 7.

$$\frac{1}{6561}+\frac{16}{3}\times \frac{1}{2187}+\frac{8!}{6!\times 2!}\times \left(\frac{2}{3}\right)^{2}\times \left(\frac{1}{3}\right)^{6}+\frac{8!}{5!\times 3!}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Egin \frac{16}{3} bider \frac{1}{2187}, zenbakitzailea zenbakitzailearekin eta izendatzailea eta izendatzailearekin biderkatuta.

$$\frac{1}{6561}+\frac{16\times 1}{3\times 2187}+\frac{8!}{6!\times 2!}\times \left(\frac{2}{3}\right)^{2}\times \left(\frac{1}{3}\right)^{6}+\frac{8!}{5!\times 3!}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Egin biderketak \frac{16\times 1}{3\times 2187} zatikian.

$$\frac{1}{6561}+\frac{16}{6561}+\frac{8!}{6!\times 2!}\times \left(\frac{2}{3}\right)^{2}\times \left(\frac{1}{3}\right)^{6}+\frac{8!}{5!\times 3!}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

\frac{1}{6561} eta \frac{16}{6561} balioek izendatzaile bera dutenez, zenbakitzaileak batu behar dituzu zatikien batura kalkulatzeko.

$$\frac{1+16}{6561}+\frac{8!}{6!\times 2!}\times \left(\frac{2}{3}\right)^{2}\times \left(\frac{1}{3}\right)^{6}+\frac{8!}{5!\times 3!}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

17 lortzeko, gehitu 1 eta 16.

$$\frac{17}{6561}+\frac{8!}{6!\times 2!}\times \left(\frac{2}{3}\right)^{2}\times \left(\frac{1}{3}\right)^{6}+\frac{8!}{5!\times 3!}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

8 balioaren faktoriala 40320 da.

$$\frac{17}{6561}+\frac{40320}{6!\times 2!}\times \left(\frac{2}{3}\right)^{2}\times \left(\frac{1}{3}\right)^{6}+\frac{8!}{5!\times 3!}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

6 balioaren faktoriala 720 da.

$$\frac{17}{6561}+\frac{40320}{720\times 2!}\times \left(\frac{2}{3}\right)^{2}\times \left(\frac{1}{3}\right)^{6}+\frac{8!}{5!\times 3!}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

2 balioaren faktoriala 2 da.

$$\frac{17}{6561}+\frac{40320}{720\times 2}\times \left(\frac{2}{3}\right)^{2}\times \left(\frac{1}{3}\right)^{6}+\frac{8!}{5!\times 3!}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

1440 lortzeko, biderkatu 720 eta 2.

$$\frac{17}{6561}+\frac{40320}{1440}\times \left(\frac{2}{3}\right)^{2}\times \left(\frac{1}{3}\right)^{6}+\frac{8!}{5!\times 3!}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

28 lortzeko, zatitu 40320 1440 balioarekin.

$$\frac{17}{6561}+28\times \left(\frac{2}{3}\right)^{2}\times \left(\frac{1}{3}\right)^{6}+\frac{8!}{5!\times 3!}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

\frac{4}{9} lortzeko, egin \frac{2}{3} ber 2.

$$\frac{17}{6561}+28\times \frac{4}{9}\times \left(\frac{1}{3}\right)^{6}+\frac{8!}{5!\times 3!}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Adierazi 28\times \frac{4}{9} frakzio bakar gisa.

$$\frac{17}{6561}+\frac{28\times 4}{9}\times \left(\frac{1}{3}\right)^{6}+\frac{8!}{5!\times 3!}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

112 lortzeko, biderkatu 28 eta 4.

$$\frac{17}{6561}+\frac{112}{9}\times \left(\frac{1}{3}\right)^{6}+\frac{8!}{5!\times 3!}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

\frac{1}{729} lortzeko, egin \frac{1}{3} ber 6.

$$\frac{17}{6561}+\frac{112}{9}\times \frac{1}{729}+\frac{8!}{5!\times 3!}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Egin \frac{112}{9} bider \frac{1}{729}, zenbakitzailea zenbakitzailearekin eta izendatzailea eta izendatzailearekin biderkatuta.

$$\frac{17}{6561}+\frac{112\times 1}{9\times 729}+\frac{8!}{5!\times 3!}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Egin biderketak \frac{112\times 1}{9\times 729} zatikian.

$$\frac{17}{6561}+\frac{112}{6561}+\frac{8!}{5!\times 3!}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

\frac{17}{6561} eta \frac{112}{6561} balioek izendatzaile bera dutenez, zenbakitzaileak batu behar dituzu zatikien batura kalkulatzeko.

$$\frac{17+112}{6561}+\frac{8!}{5!\times 3!}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

129 lortzeko, gehitu 17 eta 112.

$$\frac{129}{6561}+\frac{8!}{5!\times 3!}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Murriztu \frac{129}{6561} zatikia gai txikienera, 3 bakanduta eta ezeztatuta.

$$\frac{43}{2187}+\frac{8!}{5!\times 3!}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

8 balioaren faktoriala 40320 da.

$$\frac{43}{2187}+\frac{40320}{5!\times 3!}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

5 balioaren faktoriala 120 da.

$$\frac{43}{2187}+\frac{40320}{120\times 3!}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

3 balioaren faktoriala 6 da.

$$\frac{43}{2187}+\frac{40320}{120\times 6}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

720 lortzeko, biderkatu 120 eta 6.

$$\frac{43}{2187}+\frac{40320}{720}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

56 lortzeko, zatitu 40320 720 balioarekin.

$$\frac{43}{2187}+56\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

\frac{8}{27} lortzeko, egin \frac{2}{3} ber 3.

$$\frac{43}{2187}+56\times \frac{8}{27}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Adierazi 56\times \frac{8}{27} frakzio bakar gisa.

$$\frac{43}{2187}+\frac{56\times 8}{27}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

448 lortzeko, biderkatu 56 eta 8.

$$\frac{43}{2187}+\frac{448}{27}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

\frac{1}{243} lortzeko, egin \frac{1}{3} ber 5.

$$\frac{43}{2187}+\frac{448}{27}\times \frac{1}{243}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Egin \frac{448}{27} bider \frac{1}{243}, zenbakitzailea zenbakitzailearekin eta izendatzailea eta izendatzailearekin biderkatuta.

$$\frac{43}{2187}+\frac{448\times 1}{27\times 243}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Egin biderketak \frac{448\times 1}{27\times 243} zatikian.

$$\frac{43}{2187}+\frac{448}{6561}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

2187 eta 6561 zenbakien multiplo komun txikiena 6561 da. Bihurtu \frac{43}{2187} eta \frac{448}{6561} zatiki 6561 izendatzailearekin.

$$\frac{129}{6561}+\frac{448}{6561}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

\frac{129}{6561} eta \frac{448}{6561} balioek izendatzaile bera dutenez, zenbakitzaileak batu behar dituzu zatikien batura kalkulatzeko.

$$\frac{129+448}{6561}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

577 lortzeko, gehitu 129 eta 448.

$$\frac{577}{6561}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

8 balioaren faktoriala 40320 da.

$$\frac{577}{6561}+\frac{40320}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

4 balioaren faktoriala 24 da.

$$\frac{577}{6561}+\frac{40320}{24^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

576 lortzeko, egin 24 ber 2.

$$\frac{577}{6561}+\frac{40320}{576}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

70 lortzeko, zatitu 40320 576 balioarekin.

$$\frac{577}{6561}+70\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

\frac{16}{81} lortzeko, egin \frac{2}{3} ber 4.

$$\frac{577}{6561}+70\times \frac{16}{81}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Adierazi 70\times \frac{16}{81} frakzio bakar gisa.

$$\frac{577}{6561}+\frac{70\times 16}{81}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

1120 lortzeko, biderkatu 70 eta 16.

$$\frac{577}{6561}+\frac{1120}{81}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

\frac{1}{81} lortzeko, egin \frac{1}{3} ber 4.

$$\frac{577}{6561}+\frac{1120}{81}\times \frac{1}{81}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Egin \frac{1120}{81} bider \frac{1}{81}, zenbakitzailea zenbakitzailearekin eta izendatzailea eta izendatzailearekin biderkatuta.

$$\frac{577}{6561}+\frac{1120\times 1}{81\times 81}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Egin biderketak \frac{1120\times 1}{81\times 81} zatikian.

$$\frac{577}{6561}+\frac{1120}{6561}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

\frac{577}{6561} eta \frac{1120}{6561} balioek izendatzaile bera dutenez, zenbakitzaileak batu behar dituzu zatikien batura kalkulatzeko.

$$\frac{577+1120}{6561}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

1697 lortzeko, gehitu 577 eta 1120.

$$\frac{1697}{6561}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

8 balioaren faktoriala 40320 da.

$$\frac{1697}{6561}+\frac{40320}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

3 balioaren faktoriala 6 da.

$$\frac{1697}{6561}+\frac{40320}{6\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

5 balioaren faktoriala 120 da.

$$\frac{1697}{6561}+\frac{40320}{6\times 120}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

720 lortzeko, biderkatu 6 eta 120.

$$\frac{1697}{6561}+\frac{40320}{720}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

56 lortzeko, zatitu 40320 720 balioarekin.

$$\frac{1697}{6561}+56\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

\frac{32}{243} lortzeko, egin \frac{2}{3} ber 5.

$$\frac{1697}{6561}+56\times \frac{32}{243}\times \left(\frac{1}{3}\right)^{3}$$

Adierazi 56\times \frac{32}{243} frakzio bakar gisa.

$$\frac{1697}{6561}+\frac{56\times 32}{243}\times \left(\frac{1}{3}\right)^{3}$$

1792 lortzeko, biderkatu 56 eta 32.

$$\frac{1697}{6561}+\frac{1792}{243}\times \left(\frac{1}{3}\right)^{3}$$

\frac{1}{27} lortzeko, egin \frac{1}{3} ber 3.

$$\frac{1697}{6561}+\frac{1792}{243}\times \frac{1}{27}$$

Egin \frac{1792}{243} bider \frac{1}{27}, zenbakitzailea zenbakitzailearekin eta izendatzailea eta izendatzailearekin biderkatuta.

$$\frac{1697}{6561}+\frac{1792\times 1}{243\times 27}$$

Egin biderketak \frac{1792\times 1}{243\times 27} zatikian.

$$\frac{1697}{6561}+\frac{1792}{6561}$$

\frac{1697}{6561} eta \frac{1792}{6561} balioek izendatzaile bera dutenez, zenbakitzaileak batu behar dituzu zatikien batura kalkulatzeko.

$$\frac{1697+1792}{6561}$$

3489 lortzeko, gehitu 1697 eta 1792.

$$\frac{3489}{6561}$$

Murriztu \frac{3489}{6561} zatikia gai txikienera, 3 bakanduta eta ezeztatuta.

$$\frac{1163}{2187}$$

Faktorizatu

$$\frac{1163}{3 ^ {7}} = 0.5317786922725194$$