Resolver 20/sqrt{6-sqrt{2}} | Microsoften solucionagailu matematikoa

Ebaluatu

Azterketa

Arithmetic

antzeko 5 arazoen antzekoak:

Bilaketaren antzeko arazoak webgunean

https://socratic.org/questions/how-do-you-simplify-20-sqrt6-sqrt2

https://socratic.org/questions/how-do-you-rationalize-the-denominator-and-simplify-2-sqrt6-sqrt5

https://socratic.org/questions/how-do-you-rationalize-the-denominator-and-simplify-2sqrt-2-2sqrt-3-sqrt3

https://math.stackexchange.com/questions/1916881/if-two-curves-touch-each-other-at-some-point-find-value-of-frac2-sqrt3-a

https://socratic.org/questions/how-do-you-simplify-2sqrt3-1-sqrt3

Partekatu

Kopiatu portapapeletan

\frac{20\left(\sqrt{6}+\sqrt{2}\right)}{\left(\sqrt{6}-\sqrt{2}\right)\left(\sqrt{6}+\sqrt{2}\right)}

Adierazi \frac{20}{\sqrt{6}-\sqrt{2}} balioaren izendatzailea zenbaki arrazional gisa. Horretarako, egin zenbakitzailea eta izendatzailea bider \sqrt{6}+\sqrt{2}.

\frac{20\left(\sqrt{6}+\sqrt{2}\right)}{\left(\sqrt{6}\right)^{2}-\left(\sqrt{2}\right)^{2}}

Kasurako: \left(\sqrt{6}-\sqrt{2}\right)\left(\sqrt{6}+\sqrt{2}\right). Biderketa karratuen desberdintasun bihur daiteke arau hau erabilita: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

\frac{20\left(\sqrt{6}+\sqrt{2}\right)}{6-2}

Egin \sqrt{6} ber bi. Egin \sqrt{2} ber bi.

\frac{20\left(\sqrt{6}+\sqrt{2}\right)}{4}

4 lortzeko, 6 balioari kendu 2.

5\left(\sqrt{6}+\sqrt{2}\right)

5\left(\sqrt{6}+\sqrt{2}\right) lortzeko, zatitu 20\left(\sqrt{6}+\sqrt{2}\right) 4 balioarekin.

5\sqrt{6}+5\sqrt{2}

Erabili banaketa-propietatea 5 eta \sqrt{6}+\sqrt{2} biderkatzeko.