Lahenda n(1+b^0%)^10=100000

$$n ( 1 + b ^ { 0 } \% ) ^ { 10 } = 100000$$

Lahendage ja leidke n

$$n = \frac{10000000000000000000000000}{110462212541120451001} = 90528\frac{7,682307744912848 \times 10^{19}}{1,1046221254112045 \times 10^{20}} = 90528,69546929834$$

$$b\neq 0$$

Juhised lineaarvõrrandi lahendamiseks

Võrrand on standardkujul.

$$\frac{110462212541120451001}{100000000000000000000}n=100000$$

Jagage võrrandi mõlemad pooled väärtusega \frac{110462212541120451001}{100000000000000000000}, mis on sama nagu mõlema poole korrutamine murru pöördväärtusega.

$$\frac{\frac{110462212541120451001}{100000000000000000000}n}{\frac{110462212541120451001}{100000000000000000000}}=\frac{100000}{\frac{110462212541120451001}{100000000000000000000}}$$

\frac{110462212541120451001}{100000000000000000000}-ga jagamine võtab \frac{110462212541120451001}{100000000000000000000}-ga korrutamise tagasi.

$$n=\frac{100000}{\frac{110462212541120451001}{100000000000000000000}}$$

Jagage 100000 väärtusega \frac{110462212541120451001}{100000000000000000000}, korrutades 100000 väärtuse \frac{110462212541120451001}{100000000000000000000} pöördväärtusega.

$$n=\frac{10000000000000000000000000}{110462212541120451001}$$

Lahendage ja leidke b

$$b\neq 0$$

$$n = \frac{10000000000000000000000000}{110462212541120451001} = 90528\frac{7,682307744912848 \times 10^{19}}{1,1046221254112045 \times 10^{20}} = 90528,69546929834$$