Lahenda 2xy1y^2=6

$$2 x y 1 y ^ { 2 } = 6$$

Lahendage ja leidke x

$$x=\frac{3}{y_{1}y^{2}}$$

$$y\neq 0\text{ and }y_{1}\neq 0$$

Juhised lineaarvõrrandi lahendamiseks

Võrrand on standardkujul.

$$2y_{1}y^{2}x=6$$

Jagage mõlemad pooled 2y_{1}y^{2}-ga.

$$\frac{2y_{1}y^{2}x}{2y_{1}y^{2}}=\frac{6}{2y_{1}y^{2}}$$

2y_{1}y^{2}-ga jagamine võtab 2y_{1}y^{2}-ga korrutamise tagasi.

$$x=\frac{6}{2y_{1}y^{2}}$$

Jagage 6 väärtusega 2y_{1}y^{2}.

$$x=\frac{3}{y_{1}y^{2}}$$

Lahendage ja leidke y (complex solution)

$$y=-\sqrt{3}x^{-\frac{1}{2}}y_{1}^{-\frac{1}{2}}$$

$$y=\sqrt{3}x^{-\frac{1}{2}}y_{1}^{-\frac{1}{2}}\text{, }y_{1}\neq 0\text{ and }x\neq 0$$

Lahendage ja leidke y

$$y=\sqrt{\frac{3}{xy_{1}}}$$

$$y=-\sqrt{\frac{3}{xy_{1}}}\text{, }\left(y_{1}>0\text{ and }x>0\right)\text{ or }\left(x<0\text{ and }y_{1}<0\right)$$