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Sarnased probleemid veebiotsingust

Jagama

\frac{6\left(n-4\right)-30}{n-24\left(n-5\right)\left(n-4\right)}
Korrutage 4 ja 6, et leida 24.
\frac{6\left(n-9\right)}{-24\left(n-\left(-\frac{1}{48}\sqrt{1009}+\frac{217}{48}\right)\right)\left(n-\left(\frac{1}{48}\sqrt{1009}+\frac{217}{48}\right)\right)}
Kui avaldised pole juba teguriteks lahutatud, tehke seda.
\frac{n-9}{-4\left(n-\left(-\frac{1}{48}\sqrt{1009}+\frac{217}{48}\right)\right)\left(n-\left(\frac{1}{48}\sqrt{1009}+\frac{217}{48}\right)\right)}
Taandage 6 nii lugejas kui ka nimetajas.
\frac{n-9}{-4n^{2}+\frac{217}{6}n-80}
Laiendage avaldist.
\frac{6\left(n-4\right)-30}{n-24\left(n-5\right)\left(n-4\right)}
Korrutage 4 ja 6, et leida 24.
\frac{6\left(n-9\right)}{-24\left(n-\left(-\frac{1}{48}\sqrt{1009}+\frac{217}{48}\right)\right)\left(n-\left(\frac{1}{48}\sqrt{1009}+\frac{217}{48}\right)\right)}
Kui avaldised pole juba teguriteks lahutatud, tehke seda.
\frac{n-9}{-4\left(n-\left(-\frac{1}{48}\sqrt{1009}+\frac{217}{48}\right)\right)\left(n-\left(\frac{1}{48}\sqrt{1009}+\frac{217}{48}\right)\right)}
Taandage 6 nii lugejas kui ka nimetajas.
\frac{n-9}{-4n^{2}+\frac{217}{6}n-80}
Laiendage avaldist.