Lahenda sinx/1^4-sin2x/2^4+sin3x/3^4

$$\frac { \sin x } { 1 ^ { 4 } } - \frac { \sin 2 x } { 2 ^ { 4 } } + \frac { \sin 3 x } { 3 ^ { 4 } }$$

Lahuta teguriteks

$$\frac{\sin(x)\left(\cos(x)\left(32\cos(x)-81\right)+640\right)}{648}$$

Lahenduse etapid

Arvutage 4 aste 1 ja leidke 1.

$$factor(\frac{\sin(x)}{1}-\frac{\sin(2x)}{2^{4}}+\frac{\sin(3x)}{3^{4}})$$

Arv jagatuna ühega annab tulemiks arvu enda.

$$factor(\sin(x)-\frac{\sin(2x)}{2^{4}}+\frac{\sin(3x)}{3^{4}})$$

Arvutage 4 aste 2 ja leidke 16.

$$factor(\sin(x)-\frac{\sin(2x)}{16}+\frac{\sin(3x)}{3^{4}})$$

Arvutage 4 aste 3 ja leidke 81.

$$factor(\sin(x)-\frac{\sin(2x)}{16}+\frac{\sin(3x)}{81})$$

Tooge \frac{1}{1296} sulgude ette.

$$\frac{1296\sin(x)-81\sin(2x)+16\sin(3x)}{1296}$$

Arvuta

$$\frac{\sin(x)\left(\cos(x)\left(32\cos(x)-81\right)+640\right)}{648}$$